Answer:
Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
Explanation:
Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.
Total Heat exchange (Q) = ∑ heat transitions
Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling
= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)
= 24j + 112,950j + 209.2j
= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
Environment, Temperature, and Food.
15.5% by mass is
equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>
<span>we know that molality = moles solute / kg solvent
<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea
</span></span></span>
Since there are 155 g
urea in 1000g solution, hence the solvent is 845 g or 0.845 kg
So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>
Answer:
What is the question needing to be answered?
Explanation:
Usually with a scientific hypothesis, you ask the question in an if, then statement. For example: If it rains outside, then the ground will be wet. It's kind of like a cause and effect statement.