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Galina-37 [17]
3 years ago
15

How many grams of BF3 would you weigh out to make the following solution: 90.0 mL of 1.20 M BF3?

Chemistry
1 answer:
Alona [7]3 years ago
6 0

Don't stay awake for too long

Don't go to bed

I'll make a cup of coffee for your head

I'll get you up and going out of bed

Yeah

I don't wanna fall asleep

I don't wanna pass away

I been thinking of our future 'cause I'll never see those days

I don't know why this has happened

But I probably deserve it

I tried to do my best

But you know that I'm not perfect

I been praying for forgiveness

You've been praying for my health

When I leave this earth

Hoping you'll find someone else

'Cause yeah, we still young there's so much we haven't done

Getting married, start a family

Watch your husband with his son

I wish it could be me

But I won't make it off this bed

I hope I go to heaven

So I see you once again

My life was kinda short

But I got so many blessings

Happy you…

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At which electrade in a voltaic cell does redaction always occar?​
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Answer:cathode

Explanation:It is also known as the galvanic cell or electrochemical cell. In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

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3 years ago
Acetone has a density of 0.7857 g/cm^3. What is the volume in milliliters of 7.70g of acetone
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Which is a reason that a chemical engineer would use a rate law for a reaction in a chemical plant?
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3 years ago
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Elenna [48]

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6 0
2 years ago
How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute
Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

M=\frac{solute moles}{solution volume}

Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L

The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:

MW=\frac{mass}{mol}

Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g

Now with the density of NaOH the milliliters of solute can be determined:

d=\frac{mass}{volume}

Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH

Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:

Solvent volume = solution volume - solute volume

Solvent volume = 1429 mL -  93.88 mL = 1335.12 mL of H2O

7 0
3 years ago
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