The answer would be 16.04.
Answer: The oxidation number of Cu decreased
Explanation: In Cu2O equation Cu has an oxidation number of
Cu+1 O-2
then in the product side Cu is represented as a single element.
The rule on oxidation number for an individual element is always O
So Cu has 0 oxidation number.
Answer:
This solution has a volume of 98.4 mL
Explanation:
Step 1: Data given
Molarity of AgClO4 solution = 1.27 mol/L
Number of moles AgClO4 = 125 mmol = 0.125 mol
Molar mass of AgClO4= 207.32 g/mol
Step 2: Calculate volume of the 1.27 M solution
Molarity = moles / volume
Volume = moles / molarity
Volume = 0.125 moles / 1.27 mol /L
Volume = 0.0984 L = 98.4 mL
This solution has a volume of 98.4 mL
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