The heat that is needed to raise the temperature of 78.4 g of aluminium from 19.4 °c to 98.6°c is 5600.77 j
<u><em>calculation</em></u>
Heat(Q) = mass(M) x specific heat capacity (C) x change in temperature(ΔT)
where;
Q=?
M = 78. 4 g
C=0.902 j/g/c
ΔT=98.6°c -19.4°c =79.2°c
Q is therefore = 78.4 g x 0.902 j/g/c x 79.2°c =5600.77 j
Answer:
Explanation:
We have two pressures, two temperatures, and one volume.
This looks like a question in which we can use the Combined Gas Law to calculate the volume.
Data:
Calculation:
Compared to carbon nanotube, carbon nanofiber (CNF) is a unique quasi-one-dimensional nanostructure with a lot of edges and flaws (CNT). Additionally, their low cost and wide availability make them a valuable nanomaterial for upcoming technology.
<h3>what are the development and characterization of Carbon Nanofiber for Additively Manufactured Piezo resistive Sensors?</h3>
In accordance with the semiconductor material's piezo resistive effect, diffusion resistance is used to manufacture piezo resistive sensors on substrates of semiconductor materials. The diffusion resistor is connected in the substrate in the form of a bridge, allowing the substrate to be employed directly as a measuring sensor element.
- Carbon nanofiber/polylactic acid filament for fused filament fabrication (FFF) and additive manufacturing (AM) strain sensors was studied for the effects of production factors.
- To investigate the effects of CNF weight fraction, extrusion temperature, and number of extrusions on sensor performance, a design of experiments (DOE) approach was used. In the initial extrusion, dry melt mixing was used to combine CNFs and powdered PLA material.
- Through the DOE procedure, it was discovered that extruding CNF/PLA material for two complete extrusions at 185 °C resulted in material with material with material with dramatically improved electrical characteristics in comparison to unmodified material.
- Piezoresistive dog-bone shaped sensors were made using the best manufacturing technique using three different sizes of 5.0, 7.5, and 10.0 wt% CNF/PLA filament.
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Answer:
151.1J
Explanation:
Given parameters:
Mass of iron = 6.21g
Initial temperature of iron = 25°C
Final temperature of iron = 79.8°C
Unknown:
Amount of heat = ?
Solution:
The amount of heat require to cause this temperature can be determined using the expression below;
H = m c (T₂ - T₁)
H is the amount of heat
m is the mass
c is the specific heat capacity
T is the temperature
Specific heat capacity of iron 0.444J/g°C
Insert the parameters and solve;
H = 6.21 x 0.444 x (79.8 - 25)
H = 151.1J
