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Trava [24]
2 years ago
13

The general form of a chemical reaction is XA plus YB yields ZAB in the equation a and B or elements in the XYNZ are coefficient

s state the mole ratios for this reaction
Chemistry
1 answer:
Katarina [22]2 years ago
4 0

Answer:The mole ratio is A:B:A+B

Explanation:when substance reacts according to John Dalton's theory,their combining ratio is often a replica of the combining moles of the reactants and that of the products. So when Amoles of X combines withB moles of Y ,they produce A+B moles of XY to get a balance reaction e.g if 1moles of X2 reacts with 1moles of Y2 to form XY

The balance equation is seen as

X2+Y2_____2XY

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How to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solutio?
kirill115 [55]

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

2.5 M x V1 = 1.0 M x .250 L

<span>V1 = 0.10 L or 100 mL of the 2.5 M HCl solution is needed

Hope this helps.</span>
4 0
3 years ago
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What does a computational geneticist do?
Zielflug [23.3K]

Answer: Computational genomics (often referred to as Computational Genetics) refers to the use of computational and statistical analysis to decipher biology from genome sequences and related data, including both DNA and RNA sequence as well as other "post-genomic" data

Explanation: hope this helps

8 0
2 years ago
For which of the following will the entropy of the system increase?
snow_lady [41]

Answer :  The correct option is, (d) sublimation of dry ice.

Explanation :

Entropy : It is defined as the measurement of randomness or disorderedness in a system.

The order of entropy will be,

As we are moving from solid state to liquid state to gaseous state, the entropy will be increases due to the increase in the disorderedness.

As we are moving from gaseous state to liquid state to solid state, the entropy will be decreases due to the decrease in the disorderedness.

(a) Condensation of steam.

Condensation : It is a type of process in which the phase changes from gaseous state to liquid state at constant temperature.

In this process, phase changes from gaseous state to liquid state that means the degree of disorderedness decreases. So, the entropy will also decreases.

(b) Reaction of magnesium with oxygen to form magnesium oxide.

Mg(s)+O_2(g)\rightarrow MgO(s)

In this reaction, the randomness of reactant molecules are more (solid+gas) and as we move towards the formation of product the randomness become less (solid) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Reaction of nitrogen and hydrogen to form ammonia.

N_2(g)+H_2(g)\rightarrow NH_3(g)

In this reaction, the randomness of reactant molecules are more (2 moles of gas) and as we move towards the formation of product the randomness become less (1 mole of gas) that means the degree of disorderedness decreases. So, the entropy will also decreases.

(d) Sublimation of dry ice.

Sublimation : It is a type of process in which the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.

In this process, phase changes from solid state to gaseous state that means the degree of disorderedness increases. So, the entropy will also increases.

3 0
3 years ago
Which of the following is the correct formula for Ca2+ reacting with NO2??
mariarad [96]

Answer:

B. Ca(NO2)2

Explanation:

Ions (charged atoms) combine with one another to form stable ionic compounds. In this case, calicium ion (Ca2+) is said to react with NO2, which has a charge of -1 i.e. +1-1(2) = 1-2 = -1.

This means that calcium has a charge of +2 while nitrite ion has charge of -1, hence, when they combine, they exchange their charges, which become their subscript as follows:

Ca2+ + NO2- → Ca(NO2)2

Ca(NO2)2 is a stable ionic compound called calcium nitrite. Notice that it takes two atoms of NO2- to react with one atom of Ca2+.

5 0
3 years ago
In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
Read 2 more answers
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