Explanation:
i think 3x10^5
hope this helps if not sorry
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol
74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl
:•)
Answer:
a method of research in which a problem is identified, relevant data are gathered, a hypothesis is formulated from these data, and the hypothesis is empirically tested.
Hope this helps:)
1.) Calculate the change in pH when 4.00 ml of 0.100 M HCl(aq) is added to 0.100 mL of a buffer solution that is 0.100 M in NH3 (aq) and 0.1000 M in NH4Cl(aq).
2.) Calculate the change in pH when 4.00 mL of 0.100 M in NaOH(aq) is added to the original buffer solution.
