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STatiana [176]
4 years ago
7

A piece of string 8 inches long is cut into two pieces, one of which is of length x inches. If this piece is made into the circu

mference of a circle, and the other piece is made into the circumference of a square, then the combined area of the circle and square, as a function of x, is:
Mathematics
1 answer:
maks197457 [2]4 years ago
6 0

Answer:

2πr + 4a = 8

Step-by-step explanation:

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the area of a small square is 25 square units what is the exact length in units of a single of a large square
Furkat [3]

Answer:

5

Step-by-step explanation:

The area of any quadrilateral can be determined by multiplying the length of its base by its height. Since we know the shape here is square, we know that all sides are of equal length. From this we can work backwards by taking the square root of the area to find the length of one side.

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3 years ago
The function is y=6x.<br><br> Find the horizontal asymptote of the curve.
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y=-6x/square root (4x^2-160

Step-by-step explanation:

hope this helps please mark me brainliest

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3 years ago
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vladimir1956 [14]

Answer:

i think 60 degree is the answer

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3 years ago
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Given that the measurement is in centimeters, find the area of the circle to the nearest tenth. (Use 3.14 for π)
brilliants [131]

Answer: the Answer is b

Step-by-step explanation:

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3 years ago
Every valid argument with true premises has a true conclusion. Rewrite the above statement in the form V[x] x, if [y] then [z] (
just olya [345]

Answer:

Let y(x)="x is valid and x has true premises" and z(x)="x has a true conclusion".

Step-by-step explanation:

The universe U is the collection of all arguments so that x∈U. The statement uses the universal quantifier ∀ represented by the word "Every". The words "valid", "with true premises" and "has a true conclusions" are properties of an argument x.

We can interptet the statement as: "For all x, (x is valid and x has true premises)→(x has a true conclusion)". Symbolically, (∀x)(y(x)→z(x)). The implication → can be read as "if y(x) then z(x)".

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3 years ago
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