CaCO3(s) ⟶ CaO(s)+CO2(s)
<span>
moles CaCO3: 1.31 g/100 g/mole CaCO3= 0.0131 </span>
<span>
From stoichiometry, 1 mole of CO2 is formed per 1 mole CaCO3,
therefore 0.0131 moles CO2 should also be formed.
0.0131 moles CO2 x 44 g/mole CO2 = 0.576 g CO2 </span>
Therefore:<span>
<span>% Yield: 0.53/.576 x100= 92 percent yield</span></span>
I think that it is qualitative data
Answer:
P₂ = 2.19 atm
Explanation:
Given data:
Initial volume = 1.5 L
Initial pressure =1 atm
Initial temperature = 273K
Final temperature = 26°C (26+273 = 299 K)
Final volume = 0.75 L
Final pressure = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₂ = P₁V₁ T₂/ T₁ V₂
P₂ = 1 atm × 1.5 L × 299 K / 273 K × 0.75 L
P₂ = 448.5 atm .L. K / 204.75 K.L
P₂ = 2.19 atm
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