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AysviL [449]
3 years ago
15

Why did the alpha particles bounce back during Rutherford's experiments? They hit other alpha particles. They hit electrons. The

y hit positive charges in the gold atoms. They hit the collector film.
Physics
2 answers:
Alik [6]3 years ago
6 0
They hit positive charges in the gold atoms.
As alpha particles are positively charged particles, they will experience repulsion force as soon as they approach positive charges in the center of the atom (in the nucleus).
Also remember that back at Rutherford time, they did not have the right visualization of the atom, they had a model of it like if it was a budding of positive charges and the negative charges are put into them. So this experiment gave a really better and more reliable imagination of the atom structure.

Hope this helps.
Ainat [17]3 years ago
4 0

They hit positive charges in the gold atoms.

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A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr
IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa  

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity g=9.8m/sec^2

Specific gravity of oil = 0.600

So density of oil \rho =0.6\times 1000=600kg/m^3

We know that absolute pressure is given by P=P_0+\rho gh, here P_0=1.01\times 10^5Pa

So absolute pressure will be equal to P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa

So absolute pressure of the oil will be 102822.8 Pa

6 0
4 years ago
A net force of 125 n is applied to a certain object. as a result, the object accelerates with an acceleration of 24.0 m/s2. the
pantera1 [17]
Newton's second law states that Fnet = ma, where Fnet is the net force applied, m is the mass of the object, and a is the object's acceleration. You have the values for Fnet and a, so you simply use this equation to solve for m, mass.
8 0
4 years ago
Read 2 more answers
A cylinder with a piston contains 0.250 mol of oxygen at2.40x105 Pa and 355 K. The oxygen may be treated as an ideal gas.The gas
Nikitich [7]

Answer:

= 285 Joules

Explanation:

a) answer can be found out in attachment

(b) The temperature for the isothermal compression is the same as the temp at the end of the isobaric expansion. Since pressure is held constant but volume doubles, we use the ideal gas law:

p V = nR T          to see that the temperature also doubles.

.So...   temp for isothermal compression =   355×2 = 710 K

.(c)   The max pressure occurs at the top point. At this point, the volume is back to the original value but the temperature is twice the original value. So the pressure at this point is twice the original, or

max pressure = 2×240000 Pa =  480000 Pa  =   4.80 x 10^5 Pa

(d) total work done by the piston = workdone during isothermal compression - work done during expansion =

=  nRT ln(V initial / V final)-p (V initial - V final)

=   nRT ln(2) - nR(T final - T initial)  

= 0.250× 8.314 ×710×ln(2)-0.250×8.314× (710 - 355)

=     285 Joules

7 0
4 years ago
A car accelerates at a rate of 8.8 m/s² with a force from the tires of 15,840 N.
dezoksy [38]

Answer:

1,800kg

Explanation:

Force = Mass x Acceleration

F = m x a

15840N = m x 8.8

8.8 x m = 15840

m = 15840/8.8

= 1,800kg

4 0
2 years ago
Two identical blocks are connected to the opposite ends of a compressed spring. The blocks initially slide together on a frictio
Radda [10]

Answer:v

Explanation:

Given

Initially spring mass system is moving towards right with velocity v

Now if the spring is released left block moves towards left with a velocity \frac{v}{2}

As there is no external force applied on the system therefore the change in linear momentum is zero i.e. it is conserved

so center of mass continue to move towards the right with velocity v or we can say right block moves towards right with velocity v_{com}+\frac{3v}{2} and left block moves with velocity v_{com}-\frac{3v}{2}

5 0
3 years ago
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