Answer:
v=0.04m/s
Explanation:
To solve this problem we have to take into account the expression
where v and r are the magnitudes of the velocity and position vectors.
By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that
the maximum relative velocity is 0.04m/s
hope this helps!!
Answer:
option D
Explanation:
given,
wavelength = 600 nm
width of separation = 0.02 mm
L = 5 m
for mth order maxima
for (m+1)th order maxima
now,
and
hence,
hence, the correct answer is option D
Answer:
Explanation:
As given point p is equidistant from both the charges
It must be in the middle of both the charges
Assuming all 3 points lie on the same line
Electric Field due a charge q at a point ,distance r away
Where
Let electric field due to charge q be F1 and -q be F2
I is the distance of P from q and also from charge -q
⇒
F1
F2
⇒
F1+F2=