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weeeeeb [17]
3 years ago
9

Establish the dimension of density​

Physics
2 answers:
SpyIntel [72]3 years ago
7 0
Dimension of density = dimension of mass /dimension of volume. = M/L^3. = ML^-3.
mario62 [17]3 years ago
5 0
Dimensional Formula of Density
The dimensional formula of density is given by,

[M1 L-3 T0]
Where,

M = Mass
L = Length
T = Time
Derivation

Density (ρ) = Mass × Volume-1 . . . . . (1)

The dimensional formula of volume = [M0 L3 T0] . . . . (2)

And, the dimensional formula of mass = [M1 L0 T0] . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

Density = Mass × Volume-1

Or, (ρ) = [M1 L0 T0] × [M0 L3 T0]-1 = [M1 L-3 T0]

Therefore, density is dimensionally represented as [M1 L-3 T0].

Hope i helped!
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PtichkaEL [24]

Explanation:

Power = work / time

Power = force × distance / time

P = (650 kg) (10 m/s²) (20 m) / (15 s)

P = 8667 W

5 0
3 years ago
Below is an "oracle" function. An oracle function is a function presented interactively. When you type in a t value, and press t
Bingel [31]

Answer:

The rate of change of height with respect to time is -10.64 feet/sec

Explanation:

Given that,

There are three lines, so you can calculate three different values of the function at one time.

The function f(t) represents the height in feet of a ball thrown into the air, t seconds after it has been thrown.

Given table is,

Time t = 0, 1, 1,02

Function is,F(t)=-3.053113177191196\times10^{-18},6.000000000000134, 6.41760000000015

We need to calculate the initial height of ball

Using equation of motion

h=h_{0}+ut-\dfrac{1}{2}gt^2

Where, h₀ = initial height

u = initial velocity

t = time

g = acceleration due to gravity

At t = 0,

Put the value into the formula

-3.053113177191196\times10^{-18}=h_{0}+0-0

h_{0}=-3.053113177191196\times10^{-18}

We need to calculate the height of ball at t = 1

Using equation of motion

h_{1}=h_{0}+u_{0}t-\dfrac{1}{2}gt^2

Put the value in the equation

6.000000000000134=-3.053113177191196\times10^{-18}+u-\dfrac{1}{2}\times32

6.000000000000134+3.053113177191196\times10^{-18}+16=u_{0}

u_{0}=22\ feet/s

Velocity is the rate of change of height with respect to time

So, velocity at 1.02 sec is given

We need to calculate the height

Using equation of motion

h=ut-\dfrac{1}{2}gt^2

On differentiating w.r.to t

h'(t)=u-\dfrac{1}{2}g(2t)

Put the value into the formula

h'(t)=22-\times32\times(1.02)

h'(t)=-10.64\ feet/sec

Hence, The rate of change of height with respect to time is -10.64 feet/sec.

4 0
2 years ago
Do other planets have seasons? why
Brrunno [24]
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5 0
3 years ago
Why do objects that are thrown or shot follow a curved path
LenaWriter [7]
The initial force of the throw overcomes gravity quite easily. Then, gravity begins to bring it back down to earth, making a curved path.

8 0
3 years ago
Please help need this asap
NikAS [45]

Answer:

A)  350 N

B)  58.33 N

C)  35 kg

D)  35 kg

Explanation:

If we use that g = 10 m/s^2, then the acceleration of gravity on the Moon will be 10/6 m/s^2 = 5/3 m/s*2

The weight of the object on Earth is given by:

Weight = mass * g = 35 * 10 = 350 N

The weight of the object on the Moon:

Weight = mass * gmoon = 35 * 5/3 = 58.33 N

The mass of the object on Earth is 35 kg

The mass of the object on the Moon is exactly the same as on the Earth (35 kg) since the mass is a quantity inherent to the object and not to its location.

3 0
2 years ago
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