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Naddik [55]
3 years ago
3

A helium balloon initially at room temperature is dunked into a bucket of liquid nitrogen (T = 77 K). Which of the following wil

l occur? A) Volume increases B) Volume decreases C) The number of moles increases D) The number of moles decreases E) Temperature increases 2126970 Chem101 lu.co Introductory Che... Question 2 of 25 If two separate containers A and B have the same volume and temperature, but container A has more gaseous molecules than B, then container A will have: A) Higher pressure B) Lower presure C) A greater universal gas constant D) A smaller universal gas constant Q Introductory Che... Question 3 of 25 Which one of the following changes would cause the volume of a gas to double, assuming moles were held constant? A) Doubling pressure while keeping temperature constant. B) Doubling absolute temperature while keeping pressure constant. C) Doubling absolute temperature while cutting the pressure in half. D) Doubling the absolute temperature while doubling the pressure.
Chemistry
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

Question 1

B) Volume decreases

Question 2

A) Higher pressure

Question 3

A and B

Explanation:

Question 1

B) Volume decreases

Charles' Law: The Temperature-Volume Charles Law. It states that at constant pressure, the volume of a given amount of gas is directly proportional to temperature in Kelvin. As the temperature goes down, the volume also goes down, and vice-versa.

ogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules." For a given mass of an ideal gas, the volume and amount (moles) of

Question 2

A) Higher pressure

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules." For a given mass of an ideal gas, the amount (moles) and the volume of the gas are directly proportional at constant temperature and pressure

Increasing the number of moles increases the volume to maintain the same volume of the container with less moles the gas has to be compressed, increasing its pressure

Boyle's law is a gas law, that states that at constant temperature, the pressure and volume of a gas are inversely proportional. increasing the volume , decreases the pressure and vice versa.

Question 3

A and B

A) Doubling pressure while keeping temperature constant. B) Doubling absolute temperature while keeping pressure constant.

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Two containers hold the same radioactive isotope. Container A contains 1000 atoms, and container B contains 500 atoms. which con
enyata [817]

Answer:

The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.

Explanation:

From the question,

Container A contains 1000 atoms

Container B contains 500 atoms

<u>The rate of decay of atoms in container A is greater than the rate of decay of atoms in container B.</u>

The reason for such is due to the difference in the concentration of the isotopes. Container A which contains higher number of atoms will have the more changes of the release of the neutron as the changes of the hitting and splitting increases as the density of the atoms increases.

<u>Thus, the atoms in the container A will therefore decay faster than the atoms in the container B. </u>

8 0
4 years ago
PLEAAAASE HELP CHEM
alukav5142 [94]

Answer:

5. +5

6. +7

Explanation:

The oxidation state can be obtained as follow:

5. Oxidation state of oxygen, O = –2

Oxidation state of phosphorus, P =?

P3O10 = –5

3P + 10O = –5

3P + (10 x –2) = –5

3P – 20 = –5

Collect like terms

3P = –5 + 20

3P = 15

Divide both side by 3

P = 15/3

P = +5

Therefore, the oxidation state of P in P3O10^5- is +5

6. Oxidation state of oxygen, O = –2

Oxidation state of manganese, Mn =.?

Mn2O7 = 0

2Mn + 7O = 0

2Mn + (7 x –2) = 0

2Mn – 14 = 0

Collect like terms

2Mn = 14

Divide both side by 2

Mn = 14/2

Mn = +7

Therefore, the oxidation state of Mn in Mn2O7 is +7

4 0
3 years ago
Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is
lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
  • 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:

  • 0.6 mol CH₄ * \frac{2molH_2O}{1molCH_4} = 1.2 mol H₂O

Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:

  • 1.2 mol * 18 g/mol = 21.6 g
4 0
3 years ago
The flavoring is what seems to appeal to ______users and it’s what makes vaping seem _________
jek_recluse [69]
The flavoring is what seems to appeal to underage users and it’s what makes vaping seem harmless
4 0
2 years ago
How many molecules are in 165 g of carbon dioxide?
Svet_ta [14]
М(СО₂)=165 г

н(СО₂)=м(углекислого газа)/М(СО₂)

Н=Nₐ*м(углекислого газа)/М(СО₂)

Н=6.022*1023 * 165/44.01=2.258*10²⁴
6 0
3 years ago
Read 2 more answers
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