a micron is a millionth of a metre
Answer:
a) 2Mg + TiCl₄ ⟶ 2MgCl₂ + Ti
b) 1.02 kg
Step-by-step explanation:
a) Balanced equation
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 24.30 47.87
2Mg + TiCl₄ ⟶ 2MgCl₂ + Ti
m/kg: 1.00
b) Mass of Mg
(i) Calculate the <em>moles of Ti
</em>
n = 1.00 kg Ti × (1 kmol Ti /47.87 kg Ti)
= 0.020 89 kmol Ti
(ii) Calculate the <em>moles of Mg
</em>
The molar ratio is (2 kmol Mg/1 kmol Ti)
n = 0.020 89 kmol Ti × (2 kmol Mg/1 kmol Ti)
= 0.041 78 kmol Mg
(iii) Calculate the <em>mass of Mg
</em>
m = 0.041 78 kmol Mg × (24.30 kg Mg/1 kmol Mg)
= 1.02 kg Mg
You need 1.02 kg Mg to produce 1.00 kg Ti.
Answer:
42.875cm³ ; 422.73 cm³
Explanation:
Given that:
Volume of a cube (V) = a³
a = 3.5cm
V of a cube = (3.5cm)^3
Volume of a cube = 3.5cm * 3.5cm * 3.5cm
Volume of a cube = 42.875cm³
Volume of a Sphere, V = 4πR²
V = 4 * π * 5.8²
V = 4 * π * 33.64
V = 422.73270
V = 422.73 cm³