if 203 mL of water is added to 5.00 mL of 4.16 M KCl solution, what is the concentration of the dilute solution

The mineral benitoite is a gemstone for making jewelry. It has a molecular weight of 413.44 grams/mole and a percent composition

Mila [183]

<h3>Answer:</h3>

Option-A (BaTiSi₃O₉)

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

Moles of Ba = %Ba ÷ At.Mass of Ba

Moles of Ba = 33.21 ÷ 137.33

Moles of Ba = 0.241 mol

Moles of Ti = %Ti ÷ At.Mass of Ti

Moles of Ti = 11.58 ÷ 47.88

Moles of Ti = 0.241 mol

Moles of Si = %Si ÷ At.Mass of Si

Moles of Si = 20.38 ÷ 28.09

Moles of Si = 0.725 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 34.83 ÷ 16.0

Moles of O = 2.176 mol

Step 2: Find out mole ratio and simplify it;

Ba Ti Si O

0.241 0.241 0.725 2.176

0.241/0.241 0.241/0.241 0.725/0.241 2.176/0.241

1 1 3 9

Hence, Empirical Formula = BaTiSi₃O₉

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

Molecular Formula = n × Empirical Formula ---- (1)

Also, n is given as,

n = Molecular Weight / Empirical Formula Weight

Molecular Weight = 413.44 g.mol⁻¹

Empirical Formula Weight = 137.33 (Ba) + 47.88(Ti) + 28.09 (Si₃) + 16 (O₉) = 413.48 g.mol⁻¹

So,

n = 413.44 g.mol⁻¹ ÷ 413.48 g.mol⁻¹

n = 1

Putting Empirical Formula and value of "n" in equation 1,

Molecular Formula = 1 × BaTiSi₃O₉

Molecular Formula = BaTiSi₃O₉

6 0

3 years ago

For each set of dilutions (bleach and mouthwash), the first tube contained a 1:11 dilution (0.5 mL of agent was added to 5.0 mL

lidiya [134]

Answer:

Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5

Explanation:

In the serial dilutions for MIC test, the volume of nutrient broth in each tube should be equal: 5.0 mL. And the volume of agent in each dilution should also be similar: 0.5 mL.

The serial dilutions was as following:

Tube 1: 0.5/5.5
Tube 2: 0.5 mL of tube 1 was diluted with 5.0 mL broth. Then, the dilution of tube 2 is (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
Tube 3: We perform the similar calculation. Thus, the result is 1:1331 = 7.51 * 10^-4
Tube 4: It is 1:14641 = 6.83 * 10^-5.

5 0

3 years ago

Which influences line form

RoseWind [281]

Answer:

Line form is influenced by how fast we are writing and the pressure and also what writing instrument is used

4 0

3 years ago

An ionic compound has a solubility of 30 g per 100 mL of water at room temperature. A solution containing 70 g of the compound i

Llana [10]

Answer: A. unsaturated.

Explanation:

Unsaturated solution is defined as the solution in which more solute particles can be dissolved in the solvent.

Saturated solution is defined as the solution in which no more solute particles can be dissolved in the solvent.

Supersaturated solution is defined as the solution in which more amount of solute particles is present than the solvent particles.

Given: Solubility = 30g/100ml

If 100 ml can dissolve ionic compound = 30 g

300 ml can dissolve ionic compound = $\frac{30}{100}\times 300=90g$

Thus solubility is 90g/300 ml and dissolved salt is only 70 g , the solution is said to be unsaturated.

3 0

3 years ago

PLEASE HELP!!!! <br><br> Draw a representation of John Dalton’s atomic model.

larisa [96]

Answer:

John Dalton's Atomic Model Below ⬇

Explanation:

7 0

3 years ago