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4 years ago

The benguela current, the peru current, and the california current is what

Physics

2 answers:

Scrat [10]4 years ago

7 0

Answer:

part of the North Pacific Gyre

Explanation:

kvasek [131]4 years ago

4 0

Part of the North Pacific Gyre

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An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i

Butoxors [25]

Answer: $5 m/s^{2}$

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0m$ is the rock's final height

$y_{o}=100 m$ is the rock's initial height

$V_{o}=15 m/s$ is the rock's initial velocity

$\theta=90\°$ is the angle at which the rock was thrown (directly upwards)

$t=10 s$ is the time

$g$ is the acceleration due gravity in Planet X

Then, isolating $g$ and taking into account $sin(90\°)=1$ :

$g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t)$ (2)

$g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s))$ (3)

Finally:

$g=5 m/s^{2}$ (4) This is the acceleration due gravity in Planet X

7 0

3 years ago

Why do scientists believe that light is made of waves?

skelet666 [1.2K]

Answer:

Scientists believe that light is made of waves because experiments have shown that, based on Huygens's principle, waves have the ability to bend and change direction.

Explanation:

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3 years ago

Which star does He fusion

ella [17]

The answer shall be helious

5 0

4 years ago

The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting

Monica [59]

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The equation for gravitational potential energy is GPE = mgh.

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.

8 0

4 years ago

Read 2 more answers

You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 38.5∘ from the ground with an

zheka24 [161]

The ball's horizontal position in the air is

$x=\left(27.5\dfrac{\rm m}{\rm s}\right)\cos38.5^\circ t$