A car with a velocity of 15 m/s is accelerated uniformly at the rate of 1.9 m/s2 for 6.8 s. What is its final velocity?

You and a friend each hold a lump of wet clay. Each lump has a mass of 25 grams. You each toss your lump of clay into the air, w

solniwko [45]

Answer:

a) p(total) = <0.05, 0.1, 0.1 > kg m/s

b) p = <0.05, 0.1, 0.1 > kg.m/s

c) v_f = < 1, 2, 2 > m/s

Explanation:

a.)

Mass of each lump = 25 g = 0.025 kg

Velocity of lump 1 = < -2, 0, -7 > m/s

Momentum of lump 1 = Mass×Velocity

= 0.025×< -2, 0, -7 >

= < -0.05, 0, 0.175> kg m/s

Velocity of lump 2 = < 4, 4, -3 > m/s

Momentum of lump 2 = Mass×Velocity

= 0.025×< 4, 4, -3 >

= < 0.1, 0.1, -0.075> kg m/s

Total momentum before impact = < -0.05, 0, 0.175 > + < 0.1, 0.1, -0.075>

= < 0.05, 0.1, 0.1 > kg m/s

⇒p(total) = <0.05, 0.1, 0.1 > kg m/s

b)

As we know that,

By the law of conservation of linear momentum,

The total momentum will be the same before and after the collision.

⇒Momentum of the stuck together after the collision = Total momentum of the lumps just before impact.

⇒ p = <0.05, 0.1, 0.1 > kg m/s

c)

Let the final velocity = v_f

Total mass = 0.025 + 0.025 = 0.05 kg

As

Momentum = mass ×velocity

⇒ <0.05, 0.1, 0.1 > = 0.05 ×v_f

⇒ v_f = <0.05, 0.1, 0.1 > / 0.05

= < 1, 2, 2 > m/s

⇒v_f = < 1, 2, 2 > m/s

7 0

3 years ago

What does an alpha particle consist of?

antiseptic1488 [7]

The best answer to the question '<span>What does an alpha particle consist of?' would be letter c. An alpha particle consists of 2 protons and 2 neutrons. It is a particle that has no electrons and balances out the positively charged protons. </span>

6 0

3 years ago

Read 2 more answers

Answer it fast and no spamming....! !

ExtremeBDS [4]

Answer:

When the resistances are connected in the parallel the equivalent resistance will be always less than the value of the lowest resistance in the parallel circuit.

The equivalent resistance in the parallel circuit can be calculated using the following formula.

1/R=1/R1+1/R2+1/R3

1/R= 1/10+1/20+1/30

1/R=(6+3+2)/60

1/R=11/60

R=60/11

R=5.45 Ohms

3 0

3 years ago

A parachute on a drag race car opens and changes the velocity of the car from 75 m/s to 45 m/s in 8 seconds. Calculate the avera

nikdorinn [45]

Buscalo en gugal byy

3 0

3 years ago

How much work did the movers do (horizontally) pushing a 170-kg crate 10.2 m across a rough floor without acceleration, if the e

zhannawk [14.2K]

Answer:

Work done, W = 10195.92 Joules

Explanation:

Given that,

Mass of the crate, m = 170 kg

Distance, d = 10.2 m

The coefficient of friction, $\mu=0.6$

Let W is the work done by the mover. It is given by in terms of coefficient of friction as :

$W=\mu mg\times d$

$W=0.6\times 170\times 9.8 \times 10.2$

W = 10195.92 Joules

So, the work done by the mover is 10195.92 Joules. Hence, this is the required solution.

5 0

4 years ago