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skad [1K]
3 years ago
8

A car with a velocity of 15 m/s is accelerated uniformly at the rate of 1.9 m/s2 for 6.8 s. What is its final velocity?

Physics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

33 m/s

Explanation:

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A car is traveling at a speed of 45 km/h into town. It takes the car 2 hours to get there. How far has the car traveled?
hjlf

Answer:

90 km

Explanation:

45 km per hr

2 hrs

45 x 2 = 90

90 km/2 hrs

Hope this helps!

7 0
3 years ago
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What is the formula for lithium and chlorine?
siniylev [52]
LiCl, because lithium (Li) has one positively charged ion (1+), and
chloride (Cl) has one negatively charged ion (1-), so they
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3 years ago
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The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part
svetoff [14.1K]

Answer:

B. distance/potential

Explanation:

Quizlet

5 0
3 years ago
A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and
iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g

The speed at this point would then be

v^2 = a_c r = 2gr = 2*9.8*17 = 333.2

v = \sqrt{333.2} = 18.25 m/s

2. Similarly, if T = mg, then the centripetal acceleration must be

a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0
4 years ago
13.
lisov135 [29]

The net torque on the seesaw is 294 Nm.

<h3>What is torque?</h3>

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

  • τ = mgd-m'gd'........... Equation 1

Where:

  • τ = Net torque
  • m = Jenny's mass
  • m' = Tom's mass
  • d = Jenny's distance from the pivot
  • d' = Tom's distance from the pivot
  • g = acceleration due to gravity

From the question,

Given:

  • m = 40 kg
  • m' = 30 kg
  • d = 1.5 m
  • d' = 1 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • τ = (40×1.5×9.8)-(30×1×9.8)
  • τ  = 588-294
  • τ  = 294 Nm

Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

5 0
3 years ago
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