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Lapatulllka [165]
3 years ago
8

Pe un reostat sunt scrise valorile R=220 Ω, I=0,8A. Poate fi legat acest reostat la o priza de 220V?

Physics
2 answers:
sweet [91]3 years ago
5 0

Answer:

di ko alam eh sorey

Explanation:

di ako maalam sa ganyan

mars1129 [50]3 years ago
4 0

Answer:

fi acest r=3456

Explanation:

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Digital information can be sent through the vacuum if space, but the information must be converted to wave pulses. The correct option is B.

<h3>What is digital information?</h3>

The digital information consists of data generated by the electrical systems. For examples, computers, screens, scientific calculators or any communication devices.

The electromagnetic waves do not require medium, So, they can travel through vacuum. So, Digital information can be sent through the vacuum or space.

Therefore, the correct option is B.

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How would i solve these problems, nobody in my class understands and there is a substitute
DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is 0.87 m/s^2

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

  • Horizontal component: F_x = (765)(cos 42.0^{\circ})=568.5 N
  • Vertical component: F_y = (765)(sin 42.0^{\circ})=511.9 N

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

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