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Kitty [74]
2 years ago
9

If a company uses multimedia applications in addition to normal file and database sharing, which transmission is more efficient?

Computers and Technology
1 answer:
Sonbull [250]2 years ago
3 0

The transmission that is more efficient is the full duplex transmission.

<h3>What is database?</h3>

A database simply means an organized collection of a structured information in a computer program.

In this case, when a company uses multimedia applications in addition to normal file and database sharing, the efficient transmission is the full duplex transmission.

Learn more about database on:

brainly.com/question/26096799

#SPJ12

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andrey2020 [161]

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I believe the answer is D. To keep records of transactions in different places.

Explanation:

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2 years ago
Which statement describes part of the meeting scheduling process? It is always an all-day event. It is created in a single calen
olga nikolaevna [1]

Answer:

is there a pic or something, sorry i cant help at the time being

Explanation:

5 0
3 years ago
In Java.Use a single for loop to output odd numbers, even numbers, and an arithmetic function of an odd and even number. Use the
rosijanka [135]

Answer:

<em>This program is written using java programming language</em>

<em>Difficult lines are explained using comments (See Attachment for Source file)</em>

<em>Program starts here</em>

import java.util.*;

import java.lang.Math;

public class oddeven{

public static void main(String [] args)

{

 double even,odd;//Declare variables even and odd as double

 //The next iteration prints odd numbers

 for(int i = 1;i<=173;i+=2)

 {

  odd = i;

  System.out.format("%.4f",odd);//Round to 4 decimal places and print

System.out.print("\t");

 }

 System.out.print('\n');//Start printing on a new line

 //The next iteration prints even numbers

 for(int i = 0;i<=173;i+=2)

 {

  even=i;

  System.out.format("%.4f",even);//Round to 4 decimal places and print

System.out.print("\t");

 }

 System.out.print('\n');//Start printing on a new line

 double  ssqrt;//Declare ssqrt to calculate the square root of sum of even and odd numbers

 for(int i = 0;i<=173;i+=2)

 {

  ssqrt = Math.sqrt(2*i+1);//Calculate square root here

  System.out.format("%.4f",ssqrt); //Round to 4 decimal places and print

System.out.print("\t");

 }

}

}

Explanation:

Libraries are imported into the program

import java.util.*;

import java.lang.Math;

The following line declares variables even and odd as double

double even,odd;

The following iteration is used to print odd numbers  with in the range of 0 to 173

for(int i = 1;i<=173;i+=2)  {

odd = i;

System.out.format("%.4f",odd); This particular line rounds up each odd numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The following iteration is used to print even numbers  with in the range of 0 to 173

for(int i = 0;i<=173;i+=2)

{

even=i;

System.out.format("%.4f",even); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

The following code is used to start printing on a new line

System.out.print('\n');

The next statement declares ssqrt as double to calculate the square root of the sum of even and odd numbers

double  ssqrt;

for(int i = 0;i<=173;i+=2)

{

ssqrt = Math.sqrt(2*i+1);This line calculates the square root of sum of even and odd numbers

System.out.format("%.4f",ssqrt); This particular line rounds up each even numbers to 4 decimal places before printing them

System.out.print("\t"); This line prints a tab

}

Download java
7 0
3 years ago
What is a computer that provides services and connections to other computers on a network is called a ________ ?
melisa1 [442]
They are called servers .. you can also call them hosts
6 0
3 years ago
g Suppose we want to compress a text consisting of 6 characters,a, b, c, d, e, fusingthe Huffman Algorithm. Give an example for
Papessa [141]

Answer:

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

Explanation:

The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).

Where f(x) is frequency of character x.

Lets consider the scenario when

f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005

Please see attachment for image showing the steps of construction of Huffman tree:- see attachment

From the Huffman tree created, we can see that endcoding e() of each character are as follows:-

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

e(e) = 11110

e(f) = 11111

So we can see that maximum length of encoding is 5 in this case.

3 0
3 years ago
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