<span>In a popular classroom demonstration, solid sodium is added to liquid water and reacts to produce hydrogen gas and aqueous sodium hydroxide. Balanced chemical equation for this reaction is given below.
Na-sodium , H2o- water, H-hydrogen gas and NaOH- aqueous sodium hydroxide.
Two atoms of Na react with two atoms of water and this reaction will give us H (hydrogen gas) and two atoms of NaOH (aqueous sodium hydroxide).
2Na + 2 H2o = H2 +2NaOH.</span>
Answer:
Explanation:
From the question, we have been asked to find the molarity of FeCl2 having a volume of 450 mL,
We have been provided with 225 g which is proportional to 1.8 moles.
We know that molarity of any solution should be in mol/L.
1 mole contained in 1 L means it has a molarity of 1 mol/L
Let's convert 450 mL to Litres which is,
= 0.450 L
Thus,
1 mole is contained in 1L
x moles are contained in 0.450 L
Hence,
x mole/molarity = {1 mole x 1 L}/{0.450 L}
= 4 mol/L
Therefore 4 mol/L is the molar concentration.
Answer: C
Explanation:
Don’t trust the other person it’s not A
Answer:
Cl₂ is the limiting reactant.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
N₂ + 3Cl₂ —> 2NCl₃
From the balanced equation above,
1 L of N₂ reacted with 3 L of Cl₂.
Finally, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
1 L of N₂ reacted with 3 L of Cl₂.
Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.
From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.
Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.
