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Tanya [424]
3 years ago
6

If you woke up at 11:15 am and went to sleep at 1:55 am. How many hours where you awake?

Mathematics
2 answers:
dybincka [34]3 years ago
7 0

Answer: 15 hours and 10 minutes

Hope this helps!

shutvik [7]3 years ago
3 0

From 11:15 am to 11:15 pm, it is 12 hours.

From 11:15 pm to 1:15 am it is 2 hours

From 1:15 am to 1:55 am it is 40 minutes.

12 hours + 2 hours + 40 minutes = 14 hours and 40 minutes =

= 14 hours and 40/60 hours = 14 2/3 hours

Answer: 14 2/3 hours

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Answer:

56

Step-by-step explanation:

its 56 b

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3 years ago
Find an equivalent fraction for the decimal number.
kati45 [8]
Since its in the ten thousandths place it would be over 10000
so it would be 4545/10000 and now we have to reduce and 100 x 100 = 10000 and 4545 / 100 = 45 so 45/100 is an answer 
4 0
3 years ago
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The height of the triangle is 1 m greater than three times its base. The area of the triangle is 40m^2, what is the base of the
Nady [450]

Answer:

base = 5 m

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = \frac{1}{2} bh ( b is the base and h the height )

here h = 3b + 1 ( 1 m greater than 3 times the base ), hence

A = \frac{1}{2} b(3b + 1) = 40

Multiply both sides by 2

b(3b + 1) = 80 ← distribute and rearrange

3b² + b - 80 = 0 ← in standard form

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term

product = 3 × - 80 = - 240 and sum = 1

The factors are - 15 and + 16

Use these factors to split the b- term

3b² - 15b + 16b - 80 = 0 ( factor the first/second and third/fourth terms )

3b(b - 5) + 16(b - 5) = 0 ← factor out (b - 5)

(b - 5)(3b + 16) = 0

Equate each factor to zero and solve for b

b - 5 = 0 ⇒ b = 5

3b + 16 = 0 ⇒ b = - \frac{16}{3}

However, b > 0 ⇒ b = 5

The base of the triangle is 5 m

6 0
4 years ago
An angle is equal to one-third of its complement. Find the angle's measure.
artcher [175]

Let x^\circ be the measure of the angle in question. Its complement has measure (90-x)^\circ. We're told that this angle is congruent to 1/3 of its complement, so that

x^\circ=\dfrac{(90-x)^\circ}3\implies3x^\circ=(90-x)^\circ\implies4x^\circ=90^\circ\implies x=22.5^\circ

8 0
4 years ago
What is the x-coordinate of the point that divides the directed line segment from k to j into a ratio of 1:3? x = (startfraction
garik1379 [7]

The x-coordinate of the point which divide the line segment is 3.

Given the coordinates in the figure are J(1,-10) and K(9,2) and the 1:3 is the ratio in which the line segment is divided.

When the ratio of the length of a point from both line segments is m:n, the Sectional Formula can be used to get the coordinate of a point that is outside the line.

To find the x-coordinate we will use the formula x=(m/(m+n))(x₂-x₁)+x₁.

Here, m:n=1:3 and x₁=1 from the point J(1,-10) and x₂=9 from the point K(9,2).

Now, we will substitute these values in the formula, we get

x=(1/(1+3))(9-1)+1

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x=3

Hence, the x-coordinate of the point that divides the directed line segment from k to j into a ratio of 1:3 is 3 units.

Learn about line segments from here brainly.com/question/10240790

#SPJ4

4 0
2 years ago
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