Ask question

Ask question

All categories

3 years ago

10

which of the following statements is true about the triangles below? i'm guessing the fourth option??? please help

1 answer:

vichka [17]3 years ago

6 0

The two given triangles have two sides in the first equal to two sides in the second and an angle in the first equal to an angle in the second.
This means that we're looking for congruent triangles using SAS rule, this means that two sides and the included angle in one triangle are equal to the CORRESPONDING two sides and the included angle in the second triangle.

For the two given triangles:
JK = LK
NK = MK
angle JKN = angle LKM

Following this sequence, we can say that:
triangle JKN is congruent to triangle LKM

Checking the choices, we will find that the correct choice is: D

You might be interested in

In the figure below, BD bisects ∠ABC. What is the length of AB?

dimaraw [331]

Answer:

D. 12

Step-by-step explanation:

Based on the Angle Bisector theorem, the opposite sides of ∆ABC are divided into proportional segments alongside the two other sides of the triangle, as BD bisects the <ABC. This implies that:

AB/AD = CB/CD

Substitute

AB/8 = 6/4

Cross multiply

AB*4 = 6*8

AB*4 = 48

AB = 48/4

AB = 12

3 0

3 years ago

The graph of y > 1 2 x - 2 is shown. Which set contains only points that satisfy the inequality? A) {(6, 1), (-1, -3), (4, 4)

Kaylis [27]

Answer:

Option B) {(1, -1), (-3, -3), (2, 4)}

Step-by-step explanation:

<u><em>The correct inequality is </em></u>

$y>\frac{1}{2}x-2$

The solution of the inequality is the shaded area above the dashed line $y=\frac{1}{2}x-2$

see the attached figure to better understand the problem

we know that

If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution

<u><em>Verify each case</em></u>

case A) {(6, 1), (-1, -3), (4, 4)}

ordered pair (6,1)

For x=6, y=1

substitute in the inequality

$1>\frac{1}{2}(6)-2$

$1>1$ ---> is not true

therefore

The point not satisfy the inequality

case B) {(1, -1), (-3, -3), (2, 4)}

ordered pair (1,-1)

For x=1, y=-1

substitute in the inequality

$-1>\frac{1}{2}(1)-2$

$-1>-1.5$ ---> is true

so

The point satisfy the inequality

ordered pair (-3,3)

For x=-3, y=3

substitute in the inequality

$3>\frac{1}{2}(-3)-2$

$3>-3.5$ ---> is true

so

The point satisfy the inequality

ordered pair (2,4)

For x=2, y=4

substitute in the inequality

$4>\frac{1}{2}(2)-2$

$4>-1$ ---> is true

so

The point satisfy the inequality

therefore

The set contains only points that satisfy the inequality

case C) {(1, -1), (-3, -3), (4, -2)}

ordered pair (4,-2)

For x=4, y=-2

substitute in the inequality

$-2>\frac{1}{2}(4)-2$

$-2>0$ ---> is not true

therefore

The point not satisfy the inequality

case D) {(-1, -3), (-3, -3), (2, 4)}

ordered pair (-1,-3)

For x=-1, y=-3

substitute in the inequality

$-3>\frac{1}{2}(-1)-2$

$-3>-2.5$ ---> is not true

therefore

The point not satisfy the inequality

4 0

3 years ago

Make b the subject a= 1/4 b

dalvyx [7]

<u>Answer</u>:

b = 4a

<u>Step-by-step explanation</u>:

$a = \frac{b}{4}$

$b = 4a$

<em>changing sides changes sign division to multiplication.</em>

3 0

2 years ago

Read 2 more answers

Can 1 be expressed as a fraction

elixir [45]

<em><u>Any integer can be written as a fraction! Just put that integer as the numerator of a fraction with a denominator of 1.</u></em>

<h2><em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>!</u></em></h2><h2><em><u>#</u></em><em><u>c</u></em><em><u>a</u></em><em><u>r</u></em><em><u>r</u></em><em><u>y</u></em><em><u> </u></em><em><u>on </u></em><em><u>learning</u></em></h2>

6 0

2 years ago

Read 2 more answers

Which angle must be complementary to angle 3?<br><br><br><br> <2<br> <4<br> <5<br> <6

iogann1982 [59]

It is angle 4 because they make 90 degrees together

6 0

3 years ago

Read 2 more answers