We have the following points and their coordinates:

We must compute the distance ST between them.
The distance ST between the two points is given by:
![ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},](https://tex.z-dn.net/?f=ST%3D%5Csqrt%5B%5D%7B%28x_S-x_T%29%5E2%2B%28y_S-y_T%29%5E2_%7B%7D%7D%2C)
where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.
Replacing the coordinates of the points in the formula above, we find that:
![\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20ST%3D%5Csqrt%5B%5D%7B%28-3_%7B%7D-%28-2%29_%7B%7D%29%5E2%2B%2810_%7B%7D-3_%7B%7D%29%5E2_%7B%7D%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B1%5E2%2B7%5E2%7D%2C%20%5C%5C%20ST%3D%5Csqrt%5B%5D%7B50%7D%5Ctext%7B.%7D%20%5Cend%7Bgathered%7D)
Answer: ST = √50
If two chords intersect each other inside a circle, the products of their segments are equal.
3n = 6*4
3n = 24
n = 24/3
n = 8
Answer:
0.6 cups of sugar and 1.25 cups of chocolate chips
Step-by-step explanation:
We can begin to solve this problem with a simple proportion:
=
= 
(x = the new # of sugar y = new # of chocolate chips)
In order to keep everything proportional, we must abide by the scale factor shown with the the flour.
Basically, if we're going to use three times the amount of flour we actually need, then we need to triple all our other ingredients.
We can see that the scale factor is one half, so
x = 1.2 * 0.5
and
y = 2.5 * 0.5
This means that:
x = 0.6
y = 1.25
This means that he has to use 0.6 (or 3/5) cups of sugar and 1.25 (or 9/8) cups of chocolate chips.
Add whole numbers: 2 + 6 + 8 = 16
Add fractions:
= 1/3 + 3/4 + 1/2
= (8 + 18 + 12) ÷ 24
= 38/24 or 1 14/24 or simplified to 1 7/12
Total surface area = 16 + 1 7/12 or 17 7/12