Answer:
Work done = 422.45 kJ
Explanation:
given,
weight of equipment = 6 kN
coefficient of kinetic friction = 0.05
distance up to which it is pulled = 1000 m
constant acceleration = 0.2 m/s²
Work done by the camper = ?
actual acceleration acting a'
m a = m a' - μ mg
a' = a + μ g
a' = 0.2 + 0.05 x 9.8
a' = 0.69 m/s²
Work done = Force x distance
F = m a'

F = 422.44897 N
Work done = F x d
Work done = 422.44897 x 1000
Work done = 422449 J
Work done = 422.45 kJ
Sorry most of speak english on this website so i cannot help you
Answer:
+1.33 ×
C and -1.33 ×
C respectively.
Explanation:
Electric potential (V) is the work done in moving a unit positive charge from infinity to a reference point within an electric field. It is measured in volts.
V =
............. 1
where: k is a constant = 9 ×
N
, q is the charge and r is the distance between the charges.
From equation 1,
q =
............... 2
The charge on each ball can be determined as;
given that; V = 1.2 ×
, k = 9 ×
N
and r = 1.00 m.
From equation 2,
q = 
= 1.33 ×
C
Thus, the charge on the first ball is +1.33 ×
C, while the charge on the second ball is -1.33 ×
C.
A big difference between Mathilde and Eros is that Mathilde represents a group of separate rocks whereas Eros is a solid rock.
<h3>What is an asteroid?</h3>
An asteroid is a celestial body composed of different types of rocky materials (generally clay but also silicate) and also metals (especially Fe).
An asteroid may have different sizes and some of them can be huge as dwarf planets that travel across the universe.
In conclusion, a big difference between Mathilde and Eros is that Mathilde represents a group of rocks whereas Eros is a solid rock.
Learn more about asteroids here:
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The highest frequency (f) at which the source can operate is given as:
f = 55.133Hz.
<h3>What are sinusoidal waves?</h3>
The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.
A sine wave depicts how the intensity of a variable varies over time.
<h3>What is the calculation justifying the above result?</h3>
P = (1/2) μω²A²v
300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v
Thus the wave speed is:
v = √(T/μ)
= √[(100N)/(4 X 10⁻²kg/m)
= 50m/s
300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)
⇒ ω = 346.41 1/s
ω = 346.41 1/s
= 2πf
⇒ f = 55.133Hz
Learn more about Sinusoidal waves:
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