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Maslowich
3 years ago
15

A ball is bouncing to a height that is 1/3 of the previous height after every bounce. What kind of sequence is this? How could y

ou find the total distance travelled by the ball?
Physics
1 answer:
tamaranim1 [39]3 years ago
3 0

Answer and Explanation:

The ball is bouncing to a height of 1/3 of its previous height this is a type of geometric sequence the total distance can be found by the sum of geometric sequence

For example let the initial height is 243 fit

After one bounce it will reach  243/3 =81 feet

After second bounce 81/3=27 feet

After third bounce 27/3 =9 feet

After fourth bounce 9/3 =3 feet

So a sequence is formed that is 243,81,27,9,3..........

Here r=\frac{3}{9}=\frac{1}{3}

Sum of infinite GP = \frac{a}{1-r}

From this formula we can find the total distance traveled by the ball

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amping equipment weighing 6.0 kN is pulled across a frozen lake by means of ahorizontal rope. The coecient of kinetic friction i
Harman [31]

Answer:

Work done = 422.45 kJ

Explanation:

given,                                  

weight of equipment = 6 kN      

coefficient of kinetic friction = 0.05          

distance up to which it is pulled = 1000 m

constant acceleration = 0.2 m/s²                    

Work done by the camper = ?                

actual acceleration acting a'      

m a = m a' - μ mg            

a' = a + μ g                      

a' = 0.2 + 0.05 x 9.8                

a' = 0.69 m/s²                              

Work done = Force x distance

F = m a'                                                            

F = \dfrac{6000}{9.8} \times 0.69

F = 422.44897 N                            

Work done = F x d                          

Work done = 422.44897 x 1000

Work done = 422449 J                  

Work done = 422.45 kJ            

4 0
3 years ago
un fir de cauciuc de lungimea 1 m si sectiunea 10mm patrati se alungeste acu 1 cm ce marime are forta de deformare
Nady [450]
Sorry most of speak english on this website so i cannot help you
3 0
3 years ago
Two identical metal balls of radii 2.50
shutvik [7]

Answer:

+1.33 × 10^{-7} C and -1.33 × 10^{-7} C respectively.

Explanation:

Electric potential (V) is the work done in moving a unit positive charge from infinity to a reference point within an electric field. It is measured in volts.

     V = \frac{kq}{r} ............. 1

where: k is a constant = 9 × 10^{9} Nm^{2} C^{-2}, q is the charge and r is the distance between the charges.

From equation 1,

   q = \frac{Vr}{k} ............... 2

The charge on each ball can be determined as;

given that; V = 1.2 × 10^{3}, k = 9 × 10^{9} Nm^{2} C^{-2} and r = 1.00 m.

From equation 2,

  q = \frac{1.2*10^{3} * 1.0}{9*10^{9} }

     = 1.33 × 10^{-7} C

Thus, the charge on the first ball is +1.33 × 10^{-7} C, while the charge on the second ball is -1.33 × 10^{-7} C.

3 0
3 years ago
The shoemaker-near spacecraft explored two asteroids, mathilde and eros. a big difference between them is that:________.
Oksi-84 [34.3K]

A big difference between Mathilde and Eros is that Mathilde represents a group of separate rocks whereas Eros is a solid rock.

<h3>What is an asteroid?</h3>

An asteroid is a celestial body composed of different types of rocky materials (generally clay but also silicate) and also metals (especially Fe).

An asteroid may have different sizes and some of them can be huge as dwarf planets that travel across the universe.

In conclusion, a big difference between Mathilde and Eros is that Mathilde represents a group of rocks whereas Eros is a solid rock.

Learn more about asteroids here:

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4 0
2 years ago
Sinusoidal waves 5.00 cm in amplitude are to be transmitted along a string that has a linear mass density of 4.00× 10⁻²kg /m . T
mylen [45]

The highest frequency (f) at which the source can operate is given as:

f = 55.133Hz.

<h3>What are sinusoidal waves?</h3>

The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.

A sine wave depicts how the intensity of a variable varies over time.

<h3>What is the calculation justifying the above result?</h3>

P = (1/2) μω²A²v

300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v

Thus the wave speed is:

v = √(T/μ)

= √[(100N)/(4 X 10⁻²kg/m)

= 50m/s

300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)

⇒ ω = 346.41 1/s

ω = 346.41 1/s

= 2πf

⇒ f = 55.133Hz


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7 0
2 years ago
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