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elena-s [515]
2 years ago
5

A 3.53-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. find percent composition

Physics
1 answer:
katrin2010 [14]2 years ago
7 0

The mass percent composition of aluminum is 52.9% in aluminum oxide.

Mass of the aluminum = 3.53 g

Mass of the aluminum oxide = 6.67 g.

The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.

Aluminum reacts with oxygen to form aluminum oxide.

The overall balanced equation for the reaction is,

Aluminum + Oxygen→Aluminum \: oxygen

4Al +3O _{2}→2Al _{2}O _{3}

The mass percent composition of aluminum in the aluminum oxide is,

Mass  \: percent = \frac{ Mass \:  of \:  the  \: substance}{ Mass  \: of \:  the \:  compound} \times 100

Mass  \: percent =  \frac{Mass  \: of \:  the  \: aluminum}{ Mass \:  of \:  the \:  aluminum \: oxide } \times 100

Mass \:  percent  =  \frac{3.53}{6.67 } \times 100

= 52.9 %

Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.

To know more about aluminum oxide, refer to the below link:

brainly.com/question/25869623

#SPJ4

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Answer:

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Explanation:

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Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:

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Rₑq = (35 × 20) / (35 + 20)

Rₑq = 700 / 55

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Next, we shall determine the total resistance in the circuit. This can be obtained as follow:

Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω

Resistor 3 (R₃) = 15 Ω

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R = Rₑq + R₃ (they are in series connection)

R = 12.73 + 15

R = 27.73 Ω

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I = 10 / 27.73

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3 years ago
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Answer:

-0.0789 m

Explanation:

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Answer:

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