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Burka [1]
3 years ago
5

Which of the following statements is TRUE for high-visibility clothing? A. High-visibility clothing helps to reduce insect probl

ems when exercising. B. Bright colors work to keep you cooler while exercising. C. High-visibility clothing is important to wear in areas with moving vehicles. D. none of the above
Physics
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

C. High-visibility clothing is important to wear in areas with moving vehicles.

Explanation:

plz mark as brainliest

Mazyrski [523]3 years ago
5 0
C. High-visibility clothing is important to wear in areas with moving vehicles
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At which points would the river be traveling the slowest?
Vesnalui [34]

Answer:

This would be traveling at the lower reaches.

Explanation:

A river would be traveling the fastest at the upper reaches and it becomes slower at the middle reaches and the slowest at the lower reaches. A place where water flows fast in a river is where the width is narrow and the bottom is steep. (This is just examples incase you would like to keep notes).

4 0
3 years ago
MATHPHYSSSSSSSS PLEASEEEEEE IM SORRY YOU PROBABLY HATE ME
inysia [295]

Answer:

3.1 m/s

Explanation:

First, find the time it takes for the cat to land.  Take down to be positive.

Given:

Δy = 0.61 m

v₀ = 0 m/s

a = 9.81 m/s²

Find: t

Δy = v₀ t + ½ at²

(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²

t = 0.353 s

Now find the horizontal velocity needed to travel 1.1 m in that time.

Given:

Δx = 1.1 m

a = 0 m/s²

t = 0.353 s

Find: v₀

Δx = v₀ t + ½ at²

(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²

v₀ = 3.1 m/s

3 0
2 years ago
a ball is tossed straight up in the air to a maximum height of 25 meters before returning to the point that it was thrown, where
boyakko [2]

Answer:

height=25

velocity=8

force of gravity=10

Answer =2000

5 0
2 years ago
Who will most likely have the lowest credit score. PLEASE HELP MEEE
dimulka [17.4K]

Answer:

A. usually 3 cards a year means you have little or no credit I believe

4 0
2 years ago
A basketball player jumps straight up for a ball. To do this, he lowers his body 0.310 m and then accelerates through this dista
Nastasia [14]

Answer:A)u =4.295m/s  , B)a = 29.746m/s²   C) F=3,153N

Explanation:

Using the kinematic expression  

v² = u² - 2as

where

u = initial velocity

v = final velocity

s = distance

g = acceleration due to gravity .

Given that he reaches a height of 0.940 m above the floor,

the final velocity  = 0

Here, acceleration due to gravity is acting in  opposite the initial direction of motion. So, a=-9.81 m/s.

v² = u² + 2as

0² - u² = 2 (- 9.81) × 0.940

- u² = 2 × - 9.81 × 0.920

- u² = -18.4428

cancelling the minus in both sides , we have that  

u² = 18.4428

u = √18.4428

u =4.295m/s

(b) His acceleration (in m/s2) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. m/s2

Using v² = u² + 2as

where u = initial speed of basketball player before lengthening = 0 m/s,

v = final speed of basketball player after lengthening =  4.295m/s,

a = acceleration while  straightening his legs

s = distance moved during lengthening = 0.310m

v² = u² + 2as  

 a = (v² - u²)/2s

a = (4.29m/s)² - (0 m/s)²)/(2 × 0.310m)

a = (18.4428 m²/s² - 0 m²/s²)/(0.62 m)

a = (18.4428 m²/s²/(0.62 m)

a = 29.746m/s²

c) The force (in N) he exerts on the floor to do this, given that his mass is 106 kg. N

Force= mass x acceleration.

F = 106 kg X 29.746m/s²

 F = 3,153.076 rounded to  3,153N

8 0
3 years ago
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