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Ber [7]
2 years ago
9

A steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to whic

h it must be heated in order to fit the shaft. the initial temperature is 20 deg C and the coefficient of linear expansion is 15x10^-6 per degrees celcius. calculate the stress and forced induced in the ring
okay so the stress and forced induced I can do that but the first part is confusing me because there is no final temperature.
Physics
1 answer:
MAVERICK [17]2 years ago
4 0

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

<h3>Linear expansivity </h3>

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}

where;

  • ΔT is change in temperature
  • ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
  • α is coefficient of linear expansion
  • L is original length

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

<h3>Final temperature</h3>

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

  • T₂ is final temperature
  • T₁ is initial temperature

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

Learn more about linear expansivity here: brainly.com/question/14325928

#SPJ1

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Answer:

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Explanation:

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F_{2} = Force on other side of the door by second waiter

r_{1} = distance of first force by first waiter from hinge = 0.567 m

r_{2} = distance of second force by second waiter from hinge = 0.529 m

Since the door does not move. hence the door is in equilibrium

Using equilibrium of torque by force applied by each waiter

r_{1} F_{1} = r_{2} F_{2} \\(0.567) (257) = (0.529) F_{2}\\F_{2} = 275.5 N

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A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

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You're an electrical engineer designing an alternator (the generator that charges a car's battery). Mechanical engineers specify
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Answer:

13.78 mT

Explanation:

The peak voltage ε = ωNAB where ω = angular speed of coil = 1500 rpm = 1500 × 2π/60 rad/s = 50π rad/s = 157.08 rad/s, N = number of turns of coil = 250, A = area of coil = πr² where r = radius of coil = 10 cm = 0.10 m,

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substituting the values of the variables into the equation given that ε = 17 V

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B = 13.78 mT

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