The Sl temperature scale used in science is the
2 answers:
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Answer:
ac= 15.07 m/s²
Explanation:
The Wheel rotates with a constant angular acceleration.:
Centripetal acceleration is calculated as follows:
ac =ω² *R Formula (1)
ac =v² / R Formula (2)
Kinematics of the wheel
We apply the equations of circular motion uniformly accelerated :
ωf²= ω₀² + 2αθ Formula (3)
v = ω* R Formula (4)
Where:
θ : angle that the wheel has rotated in a given time interval (rad)
α : angular acceleration (rad/s²)
ω₀ : initial angular speed ( rad/s)
ωf : final angular speed ( rad/s)
v: tangential velocity of a point on the rim ( m/s)
R : radius of wheel (m)
ac: centripetal acceleration, (m/s²)
Data:
D = 40.0 cm : diameter of the wheel
R = D/2= 40.0 cm/ 2 = 20 cm = 0.2m
α = 3.00 rad/s^2
ω₀ = 0
n = 2 revolutions : number of revolutions
θ =2πn (rad) = 2π*2 (rad) = 4π rad
Calculate of the ωf
We replace data in the formula (3)
ωf²= ω₀² + 2αθ
ωf²= 0 + 2(3)(4π)
ωf²= 24π
ωf = 8.68 rad/s
Calculate of the v
We replace data in the formula (4)
v = ω*R
v = (8.68)*(0.2)
v = 1.736 m/s
Calculate of the ac
We replace data in the formula (1)
ac = ( ω)²*(R)
ac = (8.68)²*(0.2)
ac = 15.07 m/s²
We replace data in the formula (2)
ac = v²/ R
ac = ( 1.736 )²/(0.2)
ac = 15.07 m/s²
Answer:
1.013 s
Explanation:
You can solve this problem using the equations for constant acceleration motion. The velocity at the bottom of the window can be found using this expression:
the gravity is negative as it opposes the movement.
Now, the time elapsed before the ball reappears is 2 times the time that it takes for the ball to go from the bottom of the window, reach maximum height, and reach again the bottom of the window, minus 2 times the time that it takes for the ball to travel from the top to the bottom of the window. The time that takes to the ball to reach maximum height, or in other words, to time that takes for the velocity of the ball to go from vo to 0m/s:
Then: