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4 years ago

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A. Simplify the equation that represents the value of the coins. Make it an equation that expresses the value of quarters, dimes

, and nickels. B. Is it possible to have exactly 60 pennies in $1.87? Explain.

1 answer:

sp2606 [1]4 years ago

3 0

There is a total of 13 combinations.

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Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Marizza181 [45]

Answer

test statistic $t = -2.27$

P-value $p- value = 0.0198$

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 5$

The first sample mean is $\= x_1 = 1.76 \ mm$

The first standard is $s_1 = 0.55$

The second is $sample \ size\ is\ n_2 = 11$

The second sample mean is $\= x_2 = 2.56$

The second standard deviation is $\sigma = 0.84$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

The alternative hypothesis is $H_a: \mu_1 - \mu_2 < 0$

Generally the test statistics is mathematically represented as

$t = \frac{ (\= x _1 - \= x_2) - ( \mu_1 - \mu_2)}{ \sqrt{\frac{s_1 ^2 }{ n_1 } + \frac{s_1 ^2 }{ n_1 } } }$

=> $t = \frac{ (1.76 - 2.56 ) - 0 }{ \sqrt{\frac{0.55^2 }{ 5 } + \frac{0.84^2 }{11 } } }$

=> $t = -2.27$

Generally degree of freedom is mathematically represented as

$df = n_1 + n_2 - 2$

=> $df = 5 + 11 - 2$

=> $df = 14$

From the student t distribution table the probability value to the left that corresponds to $t = -2.27$ at a degree of freedom of $df = 14$ is

$p- value = 0.0198$

6 0

3 years ago

a car is traveling on a road that makes a 12 degree angle with the ground. find the height of the car vertically once it reaches

fenix001 [56]

I'm reading your question

___________________________

Trigonometric relationship

_____________________________-

tan (12º) = side opposite/ side adjacent

Side opposite = tan (12º) * side adjancent

Side opposite = tan (12º)* 102

Side opposite = 21. 7 m

________________________

Answer

21. 7 m

7 0

1 year ago

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

<u><em>Position of particle A:-</em></u>

$x(t)=5t-5$

$y(t)=2t-k$

<em><u>Position of particles B:-</u></em>

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

Matthew opens a store credit card when he purchases a new sound system. The interest rate is 22.45%. He charges $4,120 to the ca

Nookie1986 [14]

Let

C----------------- > charges for the purchases to the credit card

<span>r------------------- > the interest rate </span>

X------------------ > total cost of the purchase

we know that

C=4120

r= 22.45%=0.2245

X=C*(1+r)

substituting the values in the formula

X=(4120)*(1+0.2245)= (4120)*(1.2245)=5044.94

the answer is $5044.94

6 0

3 years ago

Read 2 more answers

Someone PLEASE HELP ME!

Otrada [13]

<span>The graph will get flatter from –1 to 1.As you raise a proper fraction to higher even powers, you get smaller values, so the y-values get closer to the x-axis.The graph will get closer to the y-axis, or narrower.As you raise values greater than 1 (or less than –1) to higher even powers, you get larger values, so the graph increases at a faster rate.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>

4 0

3 years ago

Read 2 more answers