Question

A 0.8 g object is placed in a 159 N/C uniform electric field. Upon being released from rest, it moves 72 m in 2.9 s. Determine the object's acceleration & charge magnitude. Assume the acceleration is due to the E-field (i.e., ignore all other forces). a =

Answer 1

Answer:

The acceleration and charge are 17.122 m/s² and $8.6\times10^{-5}\ C$

Explanation:

Given that,

Mass of object = 0.8 g

Electric field = 159 N/C

Distance = 72 m

Time = 2.9 s

We know that,

The electric force is

$F = Eq$....(I)

The newton's second law

$F=ma$

Put the value of F in the equation (I)

$ma=Eq$...(II)

We calculate the acceleration

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

$a =\dfrac{2s}{t^2}$

$a=\dfrac{2\times72}{(2.9)^2}$

$a=17.122\ m/s^2$

From equation (II)

$q=\dfrac{ma}{E}$

$q=\dfrac{0.8\times10^{-3}\times17.122}{159}$

$q=0.000086148427673\ C$

$q=8.6\times10^{-5}\ C$

Hence, The acceleration and charge are 17.122 m/s² and $8.6\times10^{-5}\ C$