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STALIN [3.7K]
2 years ago
14

This demonstrates which of the following?

Physics
2 answers:
LekaFEV [45]2 years ago
5 0

Answer:

A. is the answer

Papessa [141]2 years ago
3 0
I think the answer is 8!
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Which graph shows an object that is dropped?
Olegator [25]

Answer:

I'm pretty sure it's the third one where velocity goes from positive to negative

Explanation:

the positive velocity is before the object hits the ground and the negative is after

8 0
3 years ago
On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snoho
Svetlanka [38]

Answer: part a: 19.62m

part b: 19.62 m/s

part a: 2.83 secs

Explanation:If the air resistance is ignored then the swimmer experience free fall under gravity hence

u=0

a=9.81 m/s2

t=2 secs

s=ut+0.5at^2

s=h

h=0*2+0.5*9.81*2^2\\h=19.62 meters

Part b

v=u+at\\v=0+9.81*2\\v=19.62m/s

Part c

now we have h=2*19.62=39.24

39.24=0+0.5*9.81*t^2\\t^2=8\\t=2.83 secs

4 0
3 years ago
Sodium and phosphorus combine to form Na3P. The name of this compound is .
g100num [7]
Binary ionic compound
5 0
3 years ago
Read 2 more answers
A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0
Helen [10]

Answer:

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv   m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

6 0
2 years ago
How to find out the heat capacity of a material?​
DochEvi [55]

\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}

The heat capacity is given by the expression:

\longrightarrow \sf{\triangle Q= m \triangle C  \triangle   T}

\longrightarrow \sf{Q= \: Heat}

\longrightarrow \sf{M= \: Mass}

\longrightarrow \sf{C= \: Specific \: Heat}

\longrightarrow \sf{T= \: Temperature}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\leadsto When the \bm{heat} is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in \bm{temperature} , we can then determine the specific heat "C" by simply remplazing in the expression.

5 0
1 year ago
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