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Akimi4 [234]
3 years ago
9

A train is traveling at a velocity of 90 m/s and it has to travel a distance of 2500 meters to reach the train station. How long

until the train reaches the train station?
Physics
1 answer:
Vlada [557]3 years ago
8 0

Answer:

27.7 or 28 seconds

Explanation:

2500/90=27.7

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18. A person pulls horizontally with a force of 64 N on a 14-kg box. There is a force of friction between the box and the floor
MA_775_DIABLO [31]
  • since force=massxacceleration
  • therefore acceleration=force/mass
  • the resultant force=the acting force on the object-the frictional force
  • the resultant force=64-36=28N
  • therefore the acceleration=28/14=2m/sec^2
4 0
3 years ago
You wish to cook some pasta and so take some water and heat it on a stove. If you use 2000 grams of water with an initial temper
Ronch [10]

Answer:

the stove energy went into heating water is 837.2 kJ.

Explanation:

given,

mass of water = 2000 grams

initial temperature = 0° C

Final temperature = 100° C

specific heat of water (c) = 4.186 joule/gram

energy = m c Δ T                            

            = 2000 × 4.186 × (100° - 0°)

            = 837200 J                          

             = 837.2 kJ            

hence, the stove energy went into heating water is 837.2 kJ.

3 0
3 years ago
What is a longitudinal wave?
Vedmedyk [2.9K]
The answer is 'A', they travel parallel to the direction of motion
4 0
3 years ago
Read 2 more answers
A rocket starts from rest and moves upward from the surface of the earth. For the first 10s of its motion, the vertical accelera
Naily [24]
Since the rocket’s acceleration is 3.00 m/s^3 * t, its acceleration is increasing at the rate of 3 m/s^3 each second. The equation for its velocity at a specific time is the integral of the acceleration equation. 

<span>vf = vi + 1.5 * t^2, vi = 0 </span>
<span>vf = 1.5 * 10^2 = 150 m/s </span>
This is the rocket’s velocity at 10 seconds. The equation for its height at specific time is the integral velocity equation

<span>yf = yi + 0.5 * t^3, yi = 0 </span>
<span>yf = 0.5 * 10^3 = 500 meters </span>
<span>This is the rocket’s height at 10 seconds. </span>

<span>Part B </span>
<span>What is the speed of the rocket when it is 345 m above the surface of the earth? </span>
<span>Express your answer with the appropriate units. </span>


<span>Use the equation above to determine the time. </span>

<span>345 = 0.5 * t^3 </span>
<span>t^3 = 690 </span>
<span>t = 690^⅓ </span>
<span>This is approximately 8.837 seconds. Use the following equation to determine the velocity at this time. </span>

<span>v = 1.5 * t^2 = 1.5 * (690^⅓)^2 </span>
<span>This is approximately 117 m/s. </span>


<span>The graph of height versus time is the graph of a cubic function. The graph of velocity is a parabola. The graph of acceleration versus time is line. The slope of the line is the coefficient of t. This is a very different type of problem. For the acceleration to increase, the force must be increasing. To see what this feels like slowly push the accelerator pedal of a car to the floor. Just don’t do this so long that your car is speeding!!</span>
3 0
4 years ago
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A wheel of radius 30 cm is rotating at a rate of 2.0 revolutions every 0.080 s. (A) through what angle, in radians, does the whe
Alchen [17]
A)
2revs in 0.08s
   so in 1s thats 25revs
therefore thats <u>50π radians</u> in one second

b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
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<u>v=47.123ms^-1</u>

c)
f=1/T
f=1/period for one rotation
1 rotation = 0.08/2 = 0.04
f=1/0.04
<u>f=25Hz</u>

6 0
3 years ago
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