Which of these elements has the smallest atomic radius? A. Se B. Br C. Ge D. As

Chemistry

2 answers:

Viktor [21]4 years ago

5 0

The smallest atomic radius is A.se

Anarel [89]4 years ago

4 0

Answer:

the awnsere is a se because

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0.632 mole of carbon dioxide is produced in a chemical reaction at STP. What

levacccp [35]

Answer:

V = 14.2 L

Explanation:

Given data:

Moles of CO₂ = 0.632 mol

Temperature = standard = 273 K

Pressure = standard = 1 atm

Volume of gas = ?

Solution;

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.632 mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm

V = 14.2 L/ 1

V = 14.2 L

6 0

4 years ago

How many grams (of mass m) of glucose are in 285 ml of a 5.50% (m/v) glucose solution?

ZanzabumX [31]

The percentage of glucose given is m/v. This means that the given percentage of volume consists of mass.
In this solution, percentage of glucose is 5.5% m/v.
This means that 5.5% of the volume is the mass of glucose.
Given volume is 285 mL.
Therefore mass of glucose is 5.50% of 285 mL = (5.5*285)/100
mass of glucose = 15.67 g

4 0

3 years ago

Calculate the equilibrium constant for the reaction below given that [Cl2] = 0.37 M, [H2] = 0.27 M, and [HCl] = 0.95 M at equili

cluponka [151]

Answer:

The equilibrium constant is 9.034.

Explanation:

Every reversible chemical reaction, as in this case, occurs in both directions: the reagents are transformed into products (direct reaction) and the products are transformed back into reagents ( reverse reaction).

The general way in which a reversible reaction can be written is:

aA + bB ⇔ cC + dD

where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients.

The chemical equilibrium is the state in which the direct and indirect reaction have the same reaction rate, and is expressed by a constant Kc. This constant is defined as:

$Kc=\frac{[A]^{a}*[B]^{b} }{[C]^{c} *[D]^{d} }$

This constant is equal to the multiplication of the concentrations of the products elevated to their stoichiometric coefficients divided the multiplication of the concentrations of the reactants elevated to their stoichiometric coefficients. In Kc only gases and aqueous solutions come into play and only depends on the temperature.

You have the reaction:

Cl₂(g) + H₂(g) ⇌ 2 HCl(g)

So, in this case, the constant Kc is:

$Kc=\frac{[HCl]^{2} }{[Cl_{2} ]*[H_{2}] }$