Mole ratio :
<span>5 C</span>₆<span>H</span>₆<span>CHO + 2 KMnO</span>₄<span> + 6 H</span>⁺ <span>= 5 C</span>₆<span>H</span>₆<span>COOH + 2 Mn</span>²⁺<span> + 3 H</span>₂<span>O + 2 K</span>⁺
5 moles C₆H₆CHO ------------------ 2 moles KMnO₄
1.0 moles C₆H₆CHO ---------------- ( moles of KMnO₄ )
moles of KMnO₄ = 1.0 x 2 / 5
moles of KMnO₄ = 2 / 5
= 0.40 moles of KMnO4
hope this helps!
<h3><u>Answer</u>;</h3>
a. 3 molecules 3 carbon
b. 6 molecules 18 carbon
c. 6 molecules 18 carbon
d. 5 molecules 15 carbon
e. 3 molecules 15 carbon
f. 3 molecules 15 carbon
<h3><u>Explanation</u>;</h3>
- In the Calvin cycle, carbon atoms from CO2 are ncorporated into organic molecules and then used to build three-carbon sugars, a process that is fueled by, and dependent on, ATP and NADPH from the light reactions.
- Calvin cycle take place in the stroma. Reactions of Calvin cycle are divided into three main stages: carbon fixation, reduction, and regeneration of the starting molecule.
- During carbon fixation, a CO2 molecule combines with a five carbon acceptor molecule ribulose-1,5-bisphosphate. The result is a six carbon compound that splits to two three carbon compound, 3-PGA.
- During reduction; ATP and NADPH are used to convert the 3-PGA molecules into molecules of a three-carbon sugar, glyceraldehyde-3-phosphate.
- Finally during regeneration, some G3P molecules are used to make glucose while others are recycled to regenerate RuBP acceptor.
Answer:
<h3>The answer is 0.34 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>0.34 g/mL</h3>
Hope this helps you
Ammonification is performed by bacteria to convert organic nitrogen to ammonia.
Answer:
Major product does not undergo oxidation since it is a tertiary alcohol whereas minor product undergoes oxidation to ketone as it is secondary alcohol.
Explanation:
Hello,
In this case, given the attached picture, the hydration of the 1 methylcyclohexene yields to alcohols; 1-methylcyclohexan-1-ol and 1-methylcyclohexan-2-ol. Thus, since the OH in the 1-methylcyclohexan-1-ol (major product) is bonded to a tertiary carbon (bonded with other three carbon atoms) it is not able to increase the number of oxygen bonds (oxidation) as it already attained the octet whereas the 1-methylcyclohexan-2-ol (minor product) is able to undergo oxidation to ketone as the carbon bonded to it is secondary (bonded with other two carbon atoms), so one extra bond the oxygen is allowed to be formed to carbonyl.
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