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ratelena [41]
2 years ago
8

Which aqueous solution has the lowest boiling point?

Chemistry
1 answer:
soldi70 [24.7K]2 years ago
8 0

Answer : The correct option is, (a) 1.25 M C_6H_{12}O_6

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

where,

\DeltaT_b = change in boiling point

k_b = boiling point constant

m = molality

i = Van't Hoff factor

As per question, we conclude that the molality of the given solution are same. So, the boiling point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) C_6H_{12}O_6 is a non-electrolyte solute that means they retain their molecularity, an not undergo association or dissociation.

So, Van't Hoff factor = 1

(b) The dissociation of KNO_3 will be,

KNO_3\rightarrow K^++NO_3^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(C) The dissociation of KNO_3 will be,

AlCl_3\rightarrow Al^[3+}+3Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The boiling point depends only on the Van't Hoff factor.That means lower the Van't Hoff factor, lower will be the boiling point and vice-versa.

Hence, the correct option is, (a) 1.25 M C_6H_{12}O_6

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Determine the mass of CuSO4 • 5H20 that must be used to prepare 250mL of 2.01 M CuSO4(aq).
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Given parameters:

Volume of CuSO₄ = 250mL

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Unknown:

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To solve this problem, we must write the chemical relationship between both species.;

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Now that we know the expression, it is possible to solve for the unknown mass.

First find the number of moles of CuSO₄;

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From the equation;

             1 mole of CuSO₄ is produced from 1 mole of CuSO₄.5H₂O  

So  0.5 moles of CuSO₄ will be produced from 0.5 moles of CuSO₄.5H₂O

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                                      = 0.5 x 249.6

                                     = 124.8g

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