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ratelena [41]
3 years ago
8

Which aqueous solution has the lowest boiling point?

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer : The correct option is, (a) 1.25 M C_6H_{12}O_6

Explanation :

Formula used for Elevation in boiling point :

\Delta T_b=i\times k_b\times m

where,

\DeltaT_b = change in boiling point

k_b = boiling point constant

m = molality

i = Van't Hoff factor

As per question, we conclude that the molality of the given solution are same. So, the boiling point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) C_6H_{12}O_6 is a non-electrolyte solute that means they retain their molecularity, an not undergo association or dissociation.

So, Van't Hoff factor = 1

(b) The dissociation of KNO_3 will be,

KNO_3\rightarrow K^++NO_3^-

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(C) The dissociation of KNO_3 will be,

AlCl_3\rightarrow Al^[3+}+3Cl^-

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The boiling point depends only on the Van't Hoff factor.That means lower the Van't Hoff factor, lower will be the boiling point and vice-versa.

Hence, the correct option is, (a) 1.25 M C_6H_{12}O_6

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Calculate the molality for each of the following solutions. Then, calculate the freezing-point depression ΔTF = iKFcm produced b
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Answer:

a) Cm= 3.9 m  ; ΔTf= 14.51 ºC

b) Cm= 0.21 m ; ΔTf= 0.79ºC

Explanation:

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b) In this case we have 24 g of solute in 1.5 L of solvent. We have to convert the liters of solvent to kg, and to convert the mass of solute to mol by using the molecular weight of KCl (74.55 g/mol):

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KCl is an electrolyte and when it dissolves in water, it dissociates in 2 ions: K⁺ and Cl⁻. For this, van't Hoff factor (i) is equal to 2.

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