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kvv77 [185]
3 years ago
13

Which metal atom below cannot form a cation of several different charges?

Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0
Missing question: <span>Cr, Mn, Fe, Ba, Cu.
Answer is: Ba (barium).
Barium is metal from second group of periodic table of elements. Barium looses two electrons and has oxidation number +2.
Chromium has different oxidation numbers, usually +3 and +6, iron has oxidation numbers +2 and +3, copper +1 and +2 in their compounds.</span>
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Thanks in advance ❤❤❤❤❤❤​
lesantik [10]

Answer:

A

Divide both sides by 2

m ≤9

4 0
3 years ago
Read 2 more answers
If the pKa value for a given acid is low, what does that say about the acid (is it weak or strong)?
Dmitry [639]

Answer:

If the pKa of the acid is low (negative), then the acid is strong.

Explanation:

Ka, <em>the acid ionization constant,  </em>measures the strength of an acid in a solution. Stronger acids have higher Ka values.

We defined: pKa = -log[Ka]

This function is a decreasing function, meaning that pKa will be getting smaller and smaller,  while increasing Ka (high values of Ka will have negative pKa values). Therefore, stronger acids (high values of Ka), will have low (negative) pKa values.

3 0
3 years ago
Halogens are good leaving groups in substitution reactions because leaving group ability is directly related to their being:____
Vlada [557]

Answer:

weak bases

Explanation:

Leaving groups accept electron pairs. A strong base donates an electron pair while a weak base accepts an electron pair.

Since good leaving groups must readily accept electrons, weak bases are very good leaving groups.

The order of usefulness of halogens as leaving groups is: I > Br > Cl > F

7 0
3 years ago
A liquid at room temperature with high vapor pressure has:
Elanso [62]
It’s B because of the quest
8 0
3 years ago
What is the ionic equation of Aqueous calcium bromide was mixed with aqueous gold(I) perchlorate, and a crystallized gold(I) bro
Bumek [7]

Answer:- 2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

Explanations:- It's a double replacement reaction where a precipitate of silver(I)bromide is formed. A dpuble replacement reaction in general looks as AB + CD \rightarrow AD + CB

To balance the equation we need to multiply gold compounds on both sides by 2 and the balanced equation is..

2AuClO_4(aq) + CaBr_2(aq)\rightarrow 2AuBr(s)+ Ca(ClO_4)_2(aq)

6 0
3 years ago
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