Answer:
See explanation
Explanation:
a) Nitrous oxide (N2O) has a molar mass of 44.014 amu. It has 2 nitrogen atoms each with a mass of 14.007 amu and 1 oxygen atom with a mass of 16.0 amu.
Percentage nitrogen = (2*14.007 amu/ 44.014 amu ) *100% = 63.6%
Percentage oxygen = (16 amu/44.014 amu) * 100% = 36.4 %
63.6% + 36.4% = 100%
b) Benzoic acid (C7H6O2) has a molar mass of 122.13 amu. It has 6 hydrogen atoms each with a mass of 1.01 amu; it has 7 carbon atoms each with a mass of 12.01amu and 2 oxygen atoms with a mass of 16.0 amu.
Percentage hydrogen = (6*1.01 amu / 122.13 amu)*100% = 4.96%
Percentage carbon = (7*12.01 amu/ 122.13 amu)*100% = 68.8%
Percentage oxygen = (2*16 amu/ 122.13 amu) *100% = 26.2%
c) Magnesium hydroxide (Mg(OH)2) has a molecular mass of 58.32 amu. It has 2 hydrogen atoms each with a mass of 1.01 amu; it has 1 magnesium atom with a mass of 24.3 amu and two oxygen atoms with a mass of 16.0 amu.
Percentage hydrogen = (2*1.01 amu/ 58.32 amu) *100% = 3.46 %
Percentage magnesium = (24.3 amu/58.32 amu)*100% = 41.7%
Percentage oxygen = (2*16 amu/58.32 amu)*100% = 54.9%
d) Urea CO(NH2)2 has a molecular mass of 60.064 amu. It has 2 Nitrogen atoms each with a mass of 14.007 amu, 4 hydrogen atoms each with a mass of 1.01 amu,1 carbon atom with a mass of 12.01 amu and 1 oxygen atom with a mass of 16.0 amu.
Percentage nitrogen = (2*14.007 amu/ 60.064amu)*100% = 46.6%
Percentage hydrogen = (4*1.01 amu/60.064amu)*100% = 6.72%
Percentage carbon = (12.01 amu/60.064amu)*100% = 20.0%
Percentage oxygen = (16 amu/60.064amu)*100% = 26.6%
e) Osopentyl acetate (C7H14O2) has a molecular mass of 130.2 amu. It has 14 hydrogen atoms each with a mass of 1.01 amu,7 carbon atoms each with a mass of 12.01 amu and 2 oxygen atom with a mass of 16.0 amu.
Percentage hydrogen = (14*1.01 amu/130.2 amu)*100% = 10.8%
Percentage carbon = (7*12.01 amu/130.2 amu)*100% = 64.6%
Percentage oxygen =(2*16 amu/130.2 amu)*100% = 24.6%
