When the block of iron is placed in water the volume of water that is displaced is 27.0 cm³
<u><em> calculation</em></u>
The volume water that is displaced is equal to volume of block of the iron
volume of block of iron = length x width x height
length= 3 cm
width = 3 cm
height = 3 cm
volume is therefore = 3 cm x 3 cm x 3 cm = 27 cm³ therefore the volume displaced = 27 cm³ since the volume of water displaced is equal to volume of block.
The question is incomplete. Complete question is attached below:
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Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.
The partial pressure has been defined as the pressure exerted by each gas in the mixture.
According to the Dalton's law of partial pressure, the total pressure of gas has been the sum of the partial pressure of the gases in the mixture.
The given partial pressure of gases in the mixture has been:
- Partial pressure of Nitrogen,

- Partial pressure of Oxygen,

- Partial pressure of Argon,

- Partial pressure of Helium,

- Partial pressure of Hydrogen,

The total pressure of the gaseous mixture has been:

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.
For more information about partial pressure, refer to the link:
brainly.com/question/14623719
They release carbon dioxide
The planet that orbits in a near circle is EARTH :D