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Anna [14]
3 years ago
8

A "fizz saver" pumps air under pressure into a soda bottle to keep gas from escaping. will this keep co2 in the soda bottle? exp

lain your answer.
Chemistry
1 answer:
timofeeve [1]3 years ago
5 0
<span>A fizz saver forms an airtight seal around the now-upsidedown soda bottle, and the pressure exerted by the drink and the atmospere outside pushes out the drink through the slightly-elevated spout. The CO2 gas does not fizz out because it stays at the bottom of the upside-down bottle. Thus the CO2 gas is trapped and the drink is carbonated at a longer time.</span>
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Luke and Sian want to plant a vegetable garden in their yard. A soil testing kit measures the soil pH at 5.0, but the lettuce th
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Answer:

So, Luke and Sian has to increase the pH of the soil by adding base to it.

Explanation:

The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.

pH=-\log[H^+]

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  • With decrease in hydrogen ion concentration the pH value increases.

The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.

Comparison of pH of soil:

  =  5.0 < 6.5

= High hydrogen ion concentration > High hydrogen ion concentration

So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).

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3 years ago
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As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is
chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

<em></em>

I hope it helps!

3 0
3 years ago
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