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Solnce55 [7]
4 years ago
14

The noble gases are an example of a ______ of elements. period family table

Chemistry
1 answer:
Mariulka [41]4 years ago
5 0
Periodic table of elements
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Can somebody please help me asap !!!
EastWind [94]

Answer:

Option A. 1191.49 K

Explanation:

Data obtained from the question include:

The equation for the reaction is given below:

4HCl + O2 —> 2Cl2 + 2H2O

Enthalpy (H) = +280 KJ/mol = +280000 J/mol

Entropy (S) = +235 J/Kmol

Temperature (T) =..?

The temperature at which the reaction will be feasible can be obtained as follow:

Change in entropy (ΔS) = change in enthalphy (ΔH)/T

(ΔS) = (ΔH)/T

235 = 280000/T

Cross multiply

235 x T = 280000

Divide both side by 235

T = 280000/235

T = 1191.49 K

Therefore, the temperature at which the reaction will be feasible is 1191.49 K

4 0
4 years ago
Who was the scientist responsible for the theory of evolution by natural selection?
Allushta [10]

Answer:

Charles Darwin

Explanation:

Charles Darwin is more famous than his contemporary Alfred Russel Wallace who also developed the theory of evolution by natural selection. scientist who studies living organisms.J

8 0
3 years ago
Read 2 more answers
Identify the precipitate(s) formed when solutions of na2so4(aq), ba(no3)2(aq), and nh4clo4(aq) are mixed.
Lostsunrise [7]

Answer : BaSO_{4} will be the precipitate which will be formed.


Explanation : When all the three solutions namely; NaSO_{4}  + Ba(NO_{3})_{2}  + NH_{4} ClO_{4} are mixed together a white precipitate of BaSO_{4} is formed as a product in the solution along with the soluble by product of Ammonium nitrate which is NH_{4} NO_{3} 

7 0
3 years ago
How many molecules are in 2A1203? *
Triss [41]

Answer:

6

Explanation:

2A is a molecule Argon bond. so, it's 1 + 2+ 3

5 0
1 year ago
A photon has an energy of 2.78 x 1032 J. What is its wavelength?
8090 [49]

Answer:

7.14 × 10^(-58) m

Explanation:

We are given;

Energy; E = 2.78 x 10^(32) J

Formula to find this energy is;

E = hc/λ

Where;

E is energy

h is Planck's constant with a constant value of 6.62 × 10^(-34) J/s

c is speed of light with a constant value of 3 × 10^(8) m/s

λ is wavelength

Making λ the subject, we have;

λ = hc/E

λ = (6.62 × 10^(-34) × 3 × 10^(8))/(2.78 x 10^(32))

λ = 7.14 × 10^(-58) m

3 0
3 years ago
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