How many oxygen molecules are in 22.4 liters of oxygen gas at 273 K and 101.3 kPa

2 answers:

4 0

This 273 K and 101.3 kPa is Standart conditions, so 22.4 L is 1 mol, 1 mol anything contains 6.023 x 10^23,
AnswerA

Rina8888 [55]3 years ago

3 0

Ow many oxygen molecules are in 22.4 liters of oxygen gas at 273k and 101.3kpa
First solve the number of moles of the oxygen gas by using the ideal gas equation:
PV = nRT
Where n is the number of moles
n = PV/RT
n = (101 300 Pa) (22.4 L) (1 m3/1000 L ) / ( 8.314 Pa m3 / mol K) ( 273 K)
n = 1 mol O2
the number of molecules can be solve using avogrados number 6.022x10^23 molecule / mole
molecules of one mole O2 = 6.022x 10^23 molecules

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