Answer:
The answer to your question is 2 moles of Carbon
Explanation:
Carbon-12 means it has a molecular mass of 12g / mol. Mol is defined as the number of grams of an atom in one mol.
To solve this problem, we use proportions
12 g of Carbon ---------------- 1 mol of Carbon
24 g of Carbon -------------- x
x = ( 24 g x 1 mol ) / 12 g
x = 24 / 12
x = 2 mol of Carbon
<span>The balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O
</span>1) first step is to<span> determine the molar mass you have to consult the periodic table and see the atomic mass of each element. If the element is repeated, for example 3 times, you multiple the atomic mass per 3.
C3H8= 12 x 3 + 1*8
= 44 g/mol
2)convert grams to moles so that everything will be in same unit.</span>
<span>moles are calculated by dividing mass by molar mass.
moles of C3H8= 295g / 44 g/mol
= 6.705 mol
3)By looking at the balanced equation, you can see that 1 mol of C3H8 will produce 3 moles of CO2. So if you have 6,705 moles, you will obtain x moles of CO2:
1 C3H8--------3 CO2
6,705----------x of CO2
x= 20,115 mol of CO2
</span>
4) At STP(<span>Standard Temperature and Pressure)</span> 1 mole of gas is equivalent to 22.4 liters.
1 mol of CO2-----22,4
20,115 -------------x liters
x= 20,115 x 22,4 =
450,6 liters.
Answer: The final temperature of both substances at thermal equilibrium is 301.0 K
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of gold = 31.5 g
= mass of water = 63.4 g
= final temperature = ?
= temperature of gold = 
= temperature of water = 
= specific heat of gold = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-31.5\times 0.129\times (T_{final}-342.4)=[63.4\times 4.184\times (T_{final}-300.4)]](https://tex.z-dn.net/?f=-31.5%5Ctimes%200.129%5Ctimes%20%28T_%7Bfinal%7D-342.4%29%3D%5B63.4%5Ctimes%204.184%5Ctimes%20%28T_%7Bfinal%7D-300.4%29%5D)
The final temperature of both substances at thermal equilibrium is 301.0 K
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