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Verdich [7]
3 years ago
12

Which are examples of dynamic equilibrium

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
8 0

Answer:Dynamic Equilibrium Examples. Any reaction will be in dynamic equilibrium if it's reversible and the rates of the forward and reverse reactions are equal. For example, say that you prepare a solution that is saturated with an aqueous solution of NaCl.

Explanation:

Anit [1.1K]3 years ago
3 0

Answer:

2,4,5

Explanation:

on edg

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As the pressure on the surface of a liquid decreases, the temperature at which the liquid will boil
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Answer: option (1) decreases.


Explanation:


May be you have experienced that: when you go to the beach, where the atmposhpere pressure is greater than the atmosphere pressure in places that are at higher altitudes, the water takes longer to boil. That is because the boiling temperature is greater, and you need more total heat (more time) to permit the liquid to reach that temperature.


The reason why that happens is because substances boil when the vapor pressure (the pressure of the particles of vapor over the liquid) equals the atmosphere pressure. So, when the atmposhere pressure increases, the temperature at which the vapor pressure reaches the atmosphere pressure also increases, and when the atmosphere pressure decreases, the temperature at which the vapor pressure reaches the atmosphere pressure decreases.



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Carbon dating requires that the object being tested contain
luda_lava [24]

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4 0
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A 25.00 ml sample of hydrochloric acid solution, hcl, is titrated with 0.0512 m naoh solution. the volume of naoh solution requi
Tresset [83]

A 25.00 ml sample of hydrochloric acid solution, HCl, is titrated with 0.0512 m NaOH solution. the volume of NaOH solution required is 21.68 ml  then the molarity of the HCl solution is 0.044 M .

Calculation ,

Formula used : M_{1} V_{1} =M_{2} V_{2}                            ...( i )

Where M is the molarity or concentration and V is the volume in ml .

concentration of hydrochloric acid solution ( M_{1}    ) = ?

concentration of NaOH ( M_{2} ) = 0.0512 M

volume of hydrochloric acid solution  ( V_{1} ) = 25.00 ml

volume of NaOH ( V_{2} ) =  21.68 ml

Putting the value of concentration , volume of both  in equation ( i ) we get .

M_{1}   × 25.00 ml = 0.0512 × 21.68 ml

M_{1}    = 0.0512 × 21.68 ml / 25.00 ml= 0.044 M

to learn more about hydrochloric acid solution please click here ,

brainly.com/question/24586675

#SPJ4

5 0
1 year ago
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