Answer:
See explanation below
Explanation:
The melting point (the temperature that it changes from solid to liquid) of a pure substance depends on its mass, the forces between its molecules, and the pressure of the system.
The melting point, or the freezing point, of a mixture, is a temperature between the melting point of its components. Salt has a huge negative melting point, so when it is added to the water, the melting point decreases from 0ºC to -21ºC approximately.
So, the water will only freeze again if the temperature becomes below -21ºC which is very difficult to happen.
Answer:
Washing Clothes & Dissolving Sugar
Explanation:
Think about each application:
1) Washing clothes: You kind of need water to do this, or not much washing can be done.
2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.
3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.
4) Carving a sculpture: You would use solid tool and a sold sculpture.
5) Dissolving sugar: You need a liquid to dissolve sugar!
6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.
7) A gear for a machine is a solid!
Answer:
This question is incomplete
Explanation:
Although, the question above is incomplete, however the correct option can be deduced from the explanation below.
Compounds/chemicals that dissolve in water to conduct electricity are Ionic/electrovalent compounds. Ionic compounds/salts are compounds that are held together by ionic/electrovalent bond. These compounds dissociate in water to form ions; the dissociated ions formed are the carriers of electric charges hence enabling the salt solution conduct electricity. Examples of these electrovalent/ionic compounds include NaCl, CaCl₂, CsF and MgO.
NOTE: Identify the ionic/electrovalent compounds in the options (from the completed question) to get your answer.
Answer:
[C] = 0.4248M
Explanation:
A + B ⇄ 2C
C(i) 1.68M 1.68M 0.00
ΔC -x -x +2x
C(eq) 1.68-x 1.68-x 2x
Keq = [C]²/[A][B] = (2x)²/(1.68 - x)²= 8.98 x 10⁻²
Take SqrRt of both sides => √(2x)²/(1.68 - x)² = √8.98 x 10⁻²
=> 2x/1.68 - x = 0.2895
=> 2x = 0.2895(1.68 - x)
=> 2x = 0.4863 - 0.2895x
=> 2x + 0.2895x = 0.4863
=> 2.2895x = 0.4863
=> x = 0.4863/2.2895 = 0.2124
[C] = 2x = 2(0.2124)M = 0.4248M in 'C'
Answer:
5x10⁻⁶ = [HTeH₄O₆⁺]
Explanation:
The first dissociation equilibrium of the telluric acid in water is:
H₂TeH₄O₆ + H₂O ⇄ HTeH₄O₆⁺ + H₃O⁺
Using H-H equation for telluric acid:
<em>pH = pKa + log₁₀ [HTeH₄O₆⁺] / [H₂TeH₄O₆]</em>
pKa of telluric acid is -logKa1
pKa = -log 2.0x10⁻⁸
pKa = 7.699
As concentration of [H₂TeH₄O₆] is 0.25M, replacing in H-H equation:
3.00 = 7.699+ log₁₀ [HTeH₄O₆⁺] / [0.25M]
-4.699 = log₁₀ [HTeH₄O₆⁺] / [0.25M]
2x10⁻⁵ = [HTeH₄O₆⁺] / [0.25M]
<h3>5x10⁻⁶ = [HTeH₄O₆⁺]</h3>
