<u>Answer:</u> The freezing point of solution is 2.6°C
<u>Explanation:</u>
To calculate the depression in freezing point, we use the equation:
Or,
where,
= 
Freezing point of pure solution = 5.5°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal freezing point depression constant = 5.12 K/m = 5.12 °C/m
= Given mass of solute (anthracene) = 7.99 g
= Molar mass of solute (anthracene) = 178.23 g/mol
= Mass of solvent (benzene) = 79 g
Putting values in above equation, we get:
Hence, the freezing point of solution is 2.6°C
Answer:
Half will be green and half will be striped
Explanation:
Given green skin (G) is dominant to striped skin (g).
Cucumber 1 : Heterozygous (Gg)
Cucumber 2 : Homozygous striped (gg)
When Gg X gg :
G g
g Gg gg
g Gg gg
Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.
A factor that is changed in an experiment is called the Independent Variable.
