**Answer:**

No it is not balanced

**Explanation:**

CaCl2 + 2NaHCO3 → CO2 + CaCO3 + H2O + 2NaCl

Hope this helps

**Answer:**

2.5 mL of 1.0 x 10⁻⁴ M solution needs to be added

**Explanation:**

M₁ (Molarity after dilution) = 1.0 x 10⁻⁵ M

V₁ (volume after dilution) = 25.0 mL

M₂ (molarity before dilution) = 1.0 x 10⁻⁴ M

dilution equation is written as M₁V₁ = M₂V₂

Making V₂ the subject of formula

V₂ = M₁V₁ / M₂

Substitute the parameters in the equation,

V₂ = 1.0 x 10⁻⁵ x 25.0 / 1.0 x 10⁻⁴

= 2.5 mL

Volume of the solution before dilution is **2.5 mL**

**Repeat same step for the next**

Answer: [H3O+] > [OH-] and Kw = 1 x 10 -14

Explanation:

i just had this question and tried to look it up and i got it right by guessing my bad but i hope this is ur answer as well

**Answer:**

It is stable because it's electrically neutral

It's 1 electron and 1 proton