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4 years ago

Is the equivilant of 39.3 inches

Chemistry

1 answer:

Stels [109]4 years ago

3 0

Answer:

3 mm is equal to 1.547244 inches. To do the calculation, use our online calculator. In the box next to “millimeters”, type 39.3. Once you have entered the number, the calculator displays the results. Once you have taken note of the numbers, click the reset button if you want to make other conversions.

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Write balanced ionic equations and net ionic equations for the following reactions.

Kipish [7]

The ionic equation will be:
Mg2+(aq) + 2OH-(aq) + 2H+(aq) + 2NO3-(aq) → Mg2+(aq) + 2NO3-(aq) + 2H2O(l)
And the net ionic:
2OH-(aq) + 2H+(aq) → 2H2O(l)
a Balanced equation would be:
Mg(OH)2(aq) + 2HNO3(aq) → Mg(NO3)2 (aq) + 2H2O(l)
Now thsi si so because of the standard equation which is base plus acid=Salt plus water. We need to have in mindo that Mg(OH)2 is sparingly soluble in water and is aqueous mos of the times

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3 years ago

determine the empirical and molecular formulas of a compound that gives the following analysis in math percent: 24.27% C,4.07% H

hoa [83]

Answer:

help me with this

Explanation:

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3 years ago

Which identifies an oxidation-reduction reaction? a double replacement reaction a neutralization reaction a reaction in which ox

OLga [1]

A reaction in which oxidation numbers change is the answer! :D

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7 0

4 years ago

Read 2 more answers

The natural distribution of the isotopes of a hypothetical element is 60.795% at a mass of 281.99481 u, 22.122% at a mass of 283

fenix001 [56]

Answer: The average atomic mass of the element is 283.291 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For isotope 1:

Mass of isotope 1 = 281.99481 amu

Percentage abundance of isotope 1 = 60.795 %

Fractional abundance of isotope 1 = 0.60795

For isotope 2:

Mass of isotope 2 = 283.99570 amu

Percentage abundance of isotope 2 = 22.122 %

Fractional abundance of isotope 2 = 0.22122

For isotope 3:

Mass of isotope 3 = 286.99423 amu

Percentage abundance of isotope 3 = [100 - (60.795 + 22.122)] = 17.083 %

Fractional abundance of isotope 1 = 0.17083

Putting values in equation 1, we get:

$\text{Average atomic mass of element}=[(281.99481\times 0.60795)+(283.99570\times 0.22122)+(286.99423\times 0.17083)]\\\\\text{Average atomic mass of element}=283.291amu$

Hence, the average atomic mass of the element is 283.291 amu

5 0

4 years ago

Chlorine 37 can be represented as

Ivahew [28]

Answer:

(37 is a superscript to the left of the symbol, and 17 is a subscript to the left of the symbol)

Explanation:

1) Chlorine-37 is the chlorine isotope with mass number 37.

2) The atomic mass of chlorine is 17. All the atoms of chlorine have the same atomic number (all the atoms of an element have the same atomic number). You find this number in a periodic table.

3) The isotope representation consists of:

i) The symbol of the element (Cl in this case) at the center of the representation.

ii) The mass number (37) as a superscript to the left of the symbol. That is:

iii) The atomic number (17) as a subscript to the left of the symbol. That completes the representation in this form:

5 0

4 years ago

Read 2 more answers

Is the equivilant of 39.3 inches​

Is the equivilant of 39.3 inches