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Rom4ik [11]
4 years ago
8

Which of these is a physical property?

Chemistry
2 answers:
Ber [7]4 years ago
6 0
Which of these is a physical property?A. Malleable
lukranit [14]4 years ago
3 0
Malleable is a physical property of matter 

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List three properties of metals that are a result of metallic bonds
atroni [7]
High melting point: due to delocalized electrons
ductile: because of delocalized elections, the lattice of the metal is still held tightly even after undergoing deformation
conductivity: delocalized electrons are free to roam around the metal. So an electric potential (voltage) will create a current flow through the metal
8 0
4 years ago
A student mixes 4.50 grams of sodium chloride with 1.25 grams of ammonium chloride. If no chemical reaction has occurred, she ha
Rasek [7]

this is an inert reaction.

NaCl + NH4Cl ---> NaCl + NH4Cl

The products would contain the same molecules as the reactant side due to the fact that both reactants contain Chloride.

8 0
3 years ago
In each of the given solutions, identify the solvent and the solute.
Leona [35]

Taking into account the definition of solvent and solute, you obtain that:

  • KBr is the solute and water is the solvent.
  • water is the solute and methanol is the solvent.
  • AgNO₃ is the solute and water is the solvent.

The solution is a homogeneous mixture of two or more components that have the same chemical and physical properties in a single phase. A solution is made up of two main components: the solute and the solvent.

That is, the solute and the solvent are the components of a chemical solution, that is, of a homogeneous mixture that occurs when one or more substances are dissolved in another substance.

The solute is the substance that dissolves in a solution. In solution, the solute is usually found in a lower proportion than the solvent.

Solvent, also known as solvent, is the substance in which a solute dissolves, resulting in a chemical solution. Generally, the solvent is the component that is found in the highest proportion in the solution. It will always be the solvent who will determine the state of the matter that will have the solution.

In this case,  you consider that the solute is the component in less quantity and the solvent is the major component, and you know that:

a. A solution containing 30.0 g KBr and 100.0 g of water. Then, KBr is the solute and water is the solvent.

b. A solution containing 80.0 mL of methanol and 45.0 mL of water. Then, water is the solute and methanol is the solvent.

c. A solution containing 0.5 g AgNO₃ and 15 mL of water.  Being the density of water 1 g/mL, then 15 mL contains 15 g of water. Then, AgNO₃ is the solute and water is the solvent.

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4 0
3 years ago
Calculate the molarity of 1 L of water at 20 °C given a density of 0.9982 g/mL.
MaRussiya [10]

Answer:

I have the same thing

Explanation:

7 0
3 years ago
A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us
katrin [286]

Explanation:

Actual value = 102.0 mg/dL

Calculation of absolute error and relative error for the measured value, 98.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 98.4 | = 3.6

Relative error = \frac{Absolute\ error}{Actual\ value}

                       = \frac{3.6}{102.0} = 0.03529

Calculation of absolute error and relative error for the measured value, 104.3 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 104.3 | = 2.3

Relative error = \frac{Absolute\ error}{Actual\ value}

                       = \frac{2.3}{102.0} = 0.02255

Calculation of absolute error and relative error for the measured value, 97.4 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 97.4 | = 4.6

Relative error = \frac{Absolute\ error}{Actual\ value}

                       = \frac{4.6}{102.0} = 0.04509

Calculation of absolute error and relative error for the measured value, 106.7 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 106.7 | = 4.7

Relative error = \frac{Absolute\ error}{Actual\ value}

                       = \frac{4.7}{102.0} = 0.04607

Calculation of absolute error and relative error for the measured value, 93.0 mg/dL

Absolute error = |Actual value - measured value|

                         = | 102.0 - 93 | = 9

Relative error = \frac{Absolute\ error}{Actual\ value}

                       = \frac{9}{102.0} = 0.08823

7 0
3 years ago
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