Answer:
The temperature should be 885K.
Explanation:
In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant. We convert the unit of temperature from Celsius to Kelvin: 0 = 273K -> 40 ° C = 40 + 273 = 313K
V1 / T1 = V2 / T2
2,3L/313K= 6,5L/T2
T2=6,5L/(2,3L/313K)=884, 56K
Answer : The enthalpy change of reaction is -1800 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given final reaction is,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
First we will multiply reaction 1 by 2 and reverse reaction of reaction 2 by 3 then adding both the equation, we get :
The expression for final enthalpy is,
![\Delta H=[n\times \Delta H_1]+[n\times (-\Delta H_2)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20%5CDelta%20H_1%5D%2B%5Bn%5Ctimes%20%28-%5CDelta%20H_2%29%5D)
where,
n = number of moles
![\Delta H=[2mole\times (-1680kJ/mole)]+[3\times -(-520kJ/mole)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B2mole%5Ctimes%20%28-1680kJ%2Fmole%29%5D%2B%5B3%5Ctimes%20-%28-520kJ%2Fmole%29%5D)
Therefore, the enthalpy change of reaction is -1800 kJ
Answer:
Arrow should be yeilds, THE COEFFICIENTS are mole ratios. So every 4 moles of NH3 or ammonia produce 6 moles of H2O water
You should clean up after every investigation because if you leave a mess, maybe another detective will come in and get lost because of the mess you left.
Answer:
Less
More
Explanation:
When a constraint is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.
When the volume of a reaction system in equilibrium is decreased, the equilibrium position will shift in the direction having less total number of moles.
Similarly, when the volume is increased, the equilibrium position shifts to the direction having a greater total number of moles.
