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Illusion [34]
3 years ago
6

2.3 × 10^6 - 1.8 × 10^4

Chemistry
1 answer:
kykrilka [37]3 years ago
4 0
2.282*10^{6}
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Seafloor spreading provides evidence of which of the following Earth processes?
Radda [10]
The answer would be C. Movement of crustal plates. 
8 0
3 years ago
Read 2 more answers
Gaseous ethane (CH,CH,) will react with gaseous oxygen (0,) to produce gaseous carbon dioxide (CO) and gaseous water (H2O). Supp
notka56 [123]

Answer:

0.00 g

Explanation:

We have the masses of two reactants, so this is a limiting reactant problem.  

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

Mᵣ            30.07      32.00  

              2CH₃CH₃ + 7O₂ ⟶ 4CO₂ + 6H₂O

Mass/g:      1.50          11.

2. Calculate the moles of each reactant  

\text{moles of C$_{2}$H}_{6} = \text{1.50 g C$_{2}$H}_{6} \times \dfrac{\text{1 mol C$_{2}$H}_{6}}{\text{30.07 g C$_{2}$H}_{6}} = \text{0.04988 mol C$_{2}$H}_{6}\\\\\text{moles of O}_{2} = \text{11. g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.34 mol O}_{2}

3. Calculate the moles of CO₂ we can obtain from each reactant

From ethane:

The molar ratio is 4 mol CO₂:2 mol C₂H₆

\text{Moles of CO}_{2} = \text{0.04988 mol C$_{2}$H}_{6} \times \dfrac{\text{4 mol CO}_{2}}{\text{2 mol C$_{2}$H}_{6}} = \text{0.09976 mol CO}_{2}

From oxygen:

The molar ratio is 4 mol CO₂:7 mol O₂

\text{Moles of CO}_{2} =  \text{0.34 mol O}_{2}\times \dfrac{\text{4 mol CO}_{2}}{\text{7 mol O}_{2}} = \text{0.20 mol CO}_{2}

4. Identify the limiting and excess reactants

The limiting reactant is ethane, because it gives the smaller amount of CO₂.

The excess reactant is oxygen.

5. Mass of ethane left over.

Ethane is the limiting reactant. It will be completely used up.

The mass of ethane left over will be 0.00 g.

8 0
3 years ago
Please indicate which of the compounds will yield postive results for the permanganate, ninhydrin, and ceric ammonium nitrate te
maks197457 [2]

The compounds will yield Positive results for the permanganate, ninhydrin, and ceric ammonium nitrate tests  are

permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

<h3>What is a compound?</h3>

Generally, A compound is simply defined as a substance made up of two or more different chemical elements held together by chemical bonds that are difficult to break.

In conclusion, For the permanganate test= ethene,

ninhydrin=aspasyic acid Phenylalanine

ceric ammonium nitrate test= methanol

Read more about Compound

brainly.com/question/704297

3 0
2 years ago
Have you ever tried to mix sugar with a cold drink like tea or lemonade? What happened? Explain why.
Vinvika [58]

Answer:

yes

Explanation:

it wont dissolve because when water is cold its molecules dont separate

5 0
3 years ago
Balance each skeleton reaction, use Appendix D to calculate E°cell, and state whether the reaction is spontaneous:(b) Hg₂²⁺(aq)
Olegator [25]

The given reaction is not spontaneous.

We must recognize changes in oxidation states that take place across elements in order to balance these equations. To accomplish this, keep in mind following guidelines:

A neutral element on its own has an oxidation number of zero.For a neutral molecule, the total number of oxidations must be zero.The net charge of an ion is equal to the sum of its oxidation numbers.In a compound: hydrogen prefers +1, oxygen prefers -2, fluorine prefers -1.In a compound with no oxygen present the other halogens will also prefer -1.

One of the mercury atoms is oxidized from +1 to +2 in the simple aqueous ion, for a loss of 1 electron.

Oxidation half-reaction:

0.5 Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + 1e^-

E^o _{ox} = - 0.92 V

The other mercury is reduced from +1  to zero in mercury metal, for a gain of 1 electron.

Reduction half-reaction:

0.5 Hg^{2+} _{2} (aq) + 1 e^- →Hg(l)

E^o _{red} = 0.85V

This is a disproportionation redox reaction !

Net reaction:

Hg^{2+} _{2} (aq) →Hg^{2+} (aq) + Hg (l)

E^o _{cell} = 0.85 - 0.92 = -0.07V

The cell potential is negative so this reaction is NOT spontaneous.

To learn more about the non spontaneous reaction please click on the link brainly.com/question/20358734

#SPJ4

5 0
2 years ago
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