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qwelly [4]
4 years ago
14

6. For a particular pickup truck, the percent markup is known to be 115% based on cost to the seller. If the seller paid $15,800

for the truck, what would be the percent markup be based on the sale price? (Round to the nearest tenth percent)
Mathematics
1 answer:
Neko [114]4 years ago
4 0

Answer:

  • <u>53.5 %</u>

Explanation:

You can convert the percent markup into a multiplicative factor in this way:

Base price:                     15,800 . . . (cost to the seller)

Percent mark up:           115% . . .  (based on the cost to the seller)

Sale price:                      15,800 + 115% of x = 15,800 + 115 × 15,800 /100 =

                                        = 15,800 + 1.15 × 15,800 = 15,800 (2.15) = 33,970

The markup is:

  • Markup = price paid by the seller - cost to the seller = 33,970 - 15,800   = 18,170 (notice that this is 115% of 15,800)

And <em>the percent markup based on the sale price is</em>:

  • % = (markup / sale price) × 100 = (18,700 / 33,970) × 100 =

            = 53.49 %

Rounding to the nearest tenth percent that is 53.5 %.

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Answer: Choice A

g(x) = sqrt(2x)

====================================================

Explanation:

"sqrt(x)" is shorthand for "square root of x"

f(x) = 3x^2 is given

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One way to find the answer is through trial and error. This would only apply of course if we're given a list of multiple choice answers.

------------------

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g( f(x) ) = sqrt(2 * f(x) ) .... replace every x with f(x)

g( f(x) ) = sqrt(2 * 3x^2 ) .... plug in f(x) = 3x^2

g( f(x) ) = sqrt(6x^2 )

g( f(x) ) = sqrt(x^2 * 6)

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We found the answer on the first try. So we don't need to check the others.

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