A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
I think it’s gonna be the 3rd one
I uploaded the answer here is the link : jim hb/
Answer:
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Step-by-step explanation:
The dimensions of the prism can be 2x, 2x+3 and x+6.
We first factor out the GCF of the trinomial. The GCF of the coefficients is 2. Each term has an x in common as well, so the GCF is 2x.
Factoring out the 2x, we have
2x(2x²+15x+18).
To factor the remaining trinomial, we find factors of 2*18=36 that sum to 15. 12*3 = 36 and 12+3 = 15. We split up 15x into 12x and 3x:
2x(2x²+12x+3x+18)
Now we group together the first two terms in parentheses and the last two:
2x((2x²+12x)+(3x+18))
Factor out the GCF of the first group:
2x(2x(x+6)+(3x+18))
Factor out the GCF of the second group:
2x(2x(x+6)+3(x+6))
Factoring out what these have in common,
2x(x+6)(2x+3)