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3 years ago

Here are the first five terms of a sequence.

Mathematics

1 answer:

Levart [38]3 years ago

8 0

Answer:

So the formula for the sequence is

Second term =first term + (a+nd)

Third term = second term + (a+nd)

And so on

Where n start with zero

Step-by-step explanation:

3 8 17 30 47

First term = 3

Second term = 8

Third term = 17

Fourth term = 30

Fifth term = 47

Second term - first term = 8-3=5

Third term - second term = 17-8= 9

Fourth term - third term = 30-17=13

Fifth term - fourth term = 47-30=17

So the AP is 5 9 13 17

We find out that the common difference is 9-5 = 4

The formula for nth term of the AP is

= a + nd

So the formula fir the sequence is

Second term =first term + (a+nd)

Third term = second term + (a+nd)

And so on

Where n start with zero

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Answer:

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Step-by-step explanation:

Hello, please consider the following.

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3 years ago

4 times x with an exponent of 2 plus 2 times y with an exponent of 4. X=-3 y=2

Digiron [165]

Answer:

Step-by-step explanation:

Your equation is: $4*x^{2} +2 * y^{4}$

You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

$4*(-3)^{2} +2 * 2^{4}$

First, you want to do the exponentiation (meaning you want to calculate $(-3)^{2}$ and $2^{4}$ parts). $(-3)^{2}$ equals 9 and $2^{4}$ equals 16.

So the equation now is:

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