What mechanical energy do you transfer to an object when you lift it
1 answer:
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Split the surface area into geometric shapes as shown in the figure below.
Top part
The area of one triangle is
A₁ = (1/2)*(10 cm)*(4 cm) = 20 cm²
There are 3 of these triangles.
Vertical sides..
The area of one vertical side is
A₂ = (10 cm)*(6 cm) = 60 cm²
There 3 of them.
Bottom part
The triangle is equilateral with each side = 10 cm, and each angle = 60 deg.
The area is (from the Law of Sines) equal to
A₃ = (1/2)(10 cm)*(10 cm)*sin(60) = 43.3 cm²
The total surface area is
3A₁ + 3A₂ + A₃
= 3*20 + 3*60 + 4.3
= 283.3 cm²
Answer: The surface area is 283.3 cm²
Top part
The area of one triangle is
A₁ = (1/2)*(10 cm)*(4 cm) = 20 cm²
There are 3 of these triangles.
Vertical sides..
The area of one vertical side is
A₂ = (10 cm)*(6 cm) = 60 cm²
There 3 of them.
Bottom part
The triangle is equilateral with each side = 10 cm, and each angle = 60 deg.
The area is (from the Law of Sines) equal to
A₃ = (1/2)(10 cm)*(10 cm)*sin(60) = 43.3 cm²
The total surface area is
3A₁ + 3A₂ + A₃
= 3*20 + 3*60 + 4.3
= 283.3 cm²
Answer: The surface area is 283.3 cm²
Answer:
Correct choice is D
Step-by-step explanation:
Given the system of two equations:
Fro mthe first equation
Substitute into the second equation instead of y:
Note that then the second equation will take look
Answer:
12 in
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = h(b₁ + b₂ )
where h is the height and b₁, b₂ the parallel bases
Given h = 6, b₁ = 8 and A = 60 , then
× 6 × (8 + b₂ ) = 60 , that is
3(8 + b₂ ) = 60 ( divide both sides by 3 )
8 + b₂ = 20 ( subtract 8 from both sides )
b₂ = 12
The length of the second base is 12 inches