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hram777 [196]
3 years ago
13

What mechanical energy do you transfer to an object when you lift it

Mathematics
1 answer:
gladu [14]3 years ago
4 0
...is is Kinetic Energy? I'm not positive, at all! I'm going to go do some research brb
You might be interested in
Find the area plzzzzzzxxxzzxxxzzzzzzz
nikitadnepr [17]

Step-by-step explanation:

step 1. break up the shape into 2 triangles and one rectangle

step 2. A = area of triangle 1 (t1) + area of triangle 2 (t2) + area of the rectangle (r)

step 3. t1 = (1/2)bh where b is the base and h is the height. definition of the area of a triangle.

step 4. t1 = (1/2)(3)(2) = 3ft^2.

step 5. t2 = (1/2)(3)(3) = 4.5ft^2.

step 6. r = bh where b is the base and h is the height. definition of the area of a rectangle.

step 7. r = bh = (8)(4) = 32ft^2.

step 8. A = t1 + t2 + r = 3 + 4.5 + 32 = 39.5ft^2.

5 0
3 years ago
Which of the following is a binomial with degree 4?
wel

Answer:

the answer is A

Step-by-step explanation:

hope it's help

4 0
3 years ago
¿qué edificaciones se encuentran en el mundo con el aspecto de una parábola?
Oksana_A [137]

Answer:

Una parábolase obtienecuando se corta un cono de tal maneraque el corte sea paralelo auno de sus lados, como lo muestra la grafica de la Fig. No 10. Una vez que se ha observado a la parábola en la naturaleza, pasemos a estudiarla desde el punto de vista geométrico.

5 0
3 years ago
Calculate the expected value, the variance, and the standard deviation of the given random variable X. (Round all answers to two
Tom [10]

Answer:

E (X) = 1.8

Var (X) = 0.36

σ = 0.6

Step-by-step explanation:

Solution:-

- Denote the random variable X : is the number of red marbles that Suzan has in her hand after she selects three marbles.

- Total sample space (bag) have the following quantity of colored marbles:

                Bag : { 3 Red , 2 Green }

- Suzan selects three marbles from the bag. The Event (X) defines the number of red marbles out of 3.

- The total number of outcomes / selections for randomly selecting 3 balls from the bag:

               All outcomes = 5 C 3 = 10

- The probability distribution of the random variable X, we will use combinations to determine the required probabilities:

  X = 1 red marble:

        P ( X = 1 ) : Suzan chooses 1 Red marble from the available 3 red marble and 2 green marbles.

        P ( X = 1 ) = [ 3C1*2C2 ] / all outcomes = (3*1) / 10 = 0.3

X = 2 red marble:

        P ( X = 2 ) : Suzan chooses 2 Red marble from the available 3 red marble and 1 green marbles.

        P ( X = 2 ) = [ 3C2*2C1 ] / all outcomes = (3*2) / 10 = 0.6

X = 3 red marble:

        P ( X = 3 ) : Suzan chooses 3 Red marble from the available 3 red marble.

        P ( X = 3 ) = [ 3C3] / all outcomes = (1) / 10 = 0.1

- The probability distribution is as follows:

          X :         1                 2                3

       P (X):       0.3            0.6              0.1

- The expected value E(X) for the given random variable X is:

                E ( X ) = ∑Xi*P(Xi)

                           = 1*0.3 + 2*0.6 + 3*0.1

                           =1.8

- The variance Var(X) for the given random variable X is:

                Var ( X ) = ∑Xi^2*P(Xi) - [ E(X) ] ^2

                               = 1^2*0.3 + 2^2*0.6 + 3^2*0.1 - 1.8^2

                               = 0.36

- The standard deviation for the given random variable X is:

                σ = √Var(X)

                σ = √0.36

                σ = 0.6

5 0
4 years ago
PLEASE HELP!!!!!!!!!!
Oksanka [162]

Answer:

B

Step-by-step explanation:

Data set D does not contain the value 128, which is the median value.

Data set C does not contain the outlier value 91.

Data set A contains value 168, which does not show up on the plot.

The only remaining choice is B.

_____

In order, the data values of set B are ...

... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152

The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)

6 0
3 years ago
Read 2 more answers
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