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taurus [48]
4 years ago
10

Solve 5x + 2y = 7 10x + 4y = 14

Mathematics
2 answers:
Ksivusya [100]4 years ago
8 0
These both equations are parallel so they can't be solved
5x + 2y = 7
10x + 4y = 14
melisa1 [442]4 years ago
7 0
They are parallel lines. they can't intersect.
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Evaluate 12.3p+11.9r when p=7 and r=8.
Tema [17]
Its 181.3 u just put p and r
3 0
3 years ago
A car can take 8 passengers. Write an equation to determine the number of cars, c, needed to transport, passengers.
marshall27 [118]
Maybe you can do 8 divided by 2 would equal 4 or you can do equations that equal 8.
6 0
4 years ago
a number card numbered from 1 to 30 is drawn randomly.what is the probability of getting the card having the number which is the
Kisachek [45]
<h3>Answer:    1/3</h3>

===================================================

Explanation:

A = multiples of 5 between 1 and 30

A = {5,10,15,20,25,30}

B = multiples of 6 between 1 and 30

B = {6,12,18,24,30}

There are 6 items in set A and 5 items in set B. This gives 6+5 = 11 items overall; however, notice that "30" shows up twice. So we have to subtract off 1 to account for this. This means there are 11-1 = 10 unique values that are either a multiple of 5, a multiple of 6, or a multiple of both. This is out of 30 numbers in the set {1, 2, 3, ... , 29, 30}

The probability we want is 10/30 = 1/3

6 0
2 years ago
If I roll two six-sides dice, what is the probability that the sum of the numbers that show up on the dice is 3 or less?
liq [111]

Answer:

1/12

Step-by-step explanation:

first we have to find all the possibilities of getting a sum of 3 or less: 1+1 or 1+2 and we count the second combination 2 times because the numbers can be on either of the dices so we have a total of 3 possibilities. all the possible pairimg of dice are 6*6=36 because each dice has 6 sides and we can get either of them. so the probability would be the chance of getting a sum of 3 or less divided by all the diff combination which equals 3/36 or 1/12 which is roughly around 8.3%

4 0
3 years ago
a sixth grade class has 12 boys and 24 girls consider this statement: &lt;br /&gt;for every two boys there are 4 girls do you ag
Nitella [24]
So the ratio of boys to girls is 12:24.. now, is that an equivalent ratio as 2 boys for 4 girls? or 2:4?  let's see.

\bf \cfrac{boys}{girls}\qquad 12:24\qquad \cfrac{12}{24}\implies \boxed{\cfrac{1}{2}}&#10;\\\\\\&#10;\cfrac{boys}{girls}\qquad 2:4\qquad \cfrac{2}{4}\implies \boxed{\cfrac{1}{2}}

you could start simplifying the 12/24 fraction by dividing by some common multiple, say 2, and get 6/12, then divide by 3 and get 2/4  and stop there.

then you'll notice that 12/24 is really 2/4 in disguise.
4 0
3 years ago
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