Y=3x-5
Y=5/4x+3/4
The solution to the equations is in the picture
<h3>I'll teach you how to solve (m^2-m-4)+(m+5)</h3>
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(m^2-m-4)+(m+5)
Remove parentheses:
m^2-m-4 + m+5
Group like terms:
m^2-m+m-4+5
Add similar elements:
m^2-4+5
Add/subtract the numbers:
m^2+1
Your Answer Is m^2+1
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Answer:
The total cost of 1 belt and 1 tie is $13 and $39 respectively.
Step-by-step explanation:
Given that,
The cost of 4 belts and 5 ties is $247.
Each tie costs 3 times as much as a belt.
Let the cost of a belt is x and that of a tie is y.
ATQ,
4x + 5y = 247 ...(1)
y = 3x ....(2)
Put the value of y from equation (2) in equation (1)
4x + 5(3x) = 247
4x + 15x = 247
19x = 247
x = 13
Put the value in equation (2)
y = 3x
= 3(13)
= 39
So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.
Answer:
Determine whether a relation represents a function.
Find function values.
Determine whether a function is one-to-one.
Use the vertical line test to identify functions.
Graph the functions in the library of functions.
Step-by-step explanation:
