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jolli1 [7]
3 years ago
7

/question in attachment.

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

tn= (n-1)*d

Step-by-step explanation:

Margaret [11]3 years ago
7 0

Answer:

a_n=200\cdot \frac{1}{4}^{(n-1)}

Step-by-step explanation:

Since the sequence begins with 200 and each next term in the sequence is a quarter of the previous one, an equation for this would be:

a_n=200\cdot \frac{1}{4}^{(n-1)}

You can see that this works by testing out some scenarios. For instance, the third term in the sequence:

a_3=200\cdot \frac{1}{4}^{(3-1)}= 200\cdot \frac{1}{16}=12.5

Hope this helps!

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A<br> Write an explicit formula for an, the nth term of<br> the sequence 17, 15, 13, ...
yawa3891 [41]

Tn=-2n+19

Step-by-step explanation:

Well in south africa we use Tn

Tn=a+(n-1)d

a=is the first term in the sequence which is 17

d=is the the difference between the terms which is - 2

Tn=17+(n-1)(-2)

Tn=17-2n+2

Tn=-2n+19

3 0
3 years ago
X² + 2x - 3 = 0
tankabanditka [31]

Step-by-step explanation:

x²+2x-3=0

(x²+3x)-(x-3)=0

x(x+3)-1(x+3)=0

(x-1)(x+3)=0

x=1 or x=-3

6 0
3 years ago
what is the lub and glb of the following sets, in the set of real numbe if exists E={ 0.2,0.23,0.234,0.2343,0.23434,0.23434,...}
Brums [2.3K]

Answer:

Hello,

Step-by-step explanation:

LUB(E)=0.2=\dfrac{1}{5} \\\\GUB(E)=0.2 34 34 34 ....=0.2+\dfrac{1}{10} *0.343434....\\\\=\dfrac{1}{5} +\dfrac{1}{10} *\dfrac{34}{99} \\\\=\dfrac{198+34}{990} \\\\=\dfrac{116}{495}

4 0
3 years ago
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
krek1111 [17]

Answer:

answer in the attached image

Step-by-step explanation:

hope this helps, have a nice day :)

8 0
3 years ago
Read 2 more answers
I forget how to do this,thanks for the help!
miss Akunina [59]

Answer:

x=12

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

5x+8x+2x =180

Combine like terms

15x = 180

Divide by 15 on each side

15x/15 =180/15

x=12


4 0
4 years ago
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